Solving for b_1: Help Needed with 2A=h(b_{1}+b_{2})?

  • Thread starter GLprincess02
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In summary, the equation 2A=h(b_{1}+b_{2}) can be rewritten as b_{1} = \frac{2A}{h} - b_{2}. To solve for b_{1}, you would divide both sides by h. This can help with rewriting equations.
  • #1
GLprincess02
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I know you all are probably sick of me posting these kind of "easy" problems, but rewriting equations is one of those things that I just seem to struggle with. So that being said, can I get help with [tex]2A=h(b_{1}+b_{2})[/tex]? I need to solve for [tex]b_{1}[/tex]. Maybe if someone just gave me the first step, I could get the rest ?
 
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  • #2
[tex] 2A=h(b_{1}+b_{2}) [/tex].
[tex] 2A = hb_{1}+hb_{2} [/tex].
[tex] 2A-hb_{2} = hb_{1} [/tex].

So how would you solve for [tex] b_{1} [/tex]?
 
  • #3
Wouldn't you divide both sides by h?
 
  • #4
yes you would.
 
  • #5
So the final answer would be [tex]\frac{2A-b_{2}}{h}=b_{1}[/tex] ?
 
  • #6
no it would be [tex] b_{1} = \frac{2A-hb_{2}}{h} [/tex] or [tex] b_{1} = \frac{2A}{h} - b_{2} [/tex]
 
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  • #7
Oh you're right, I just forgot the 2nd h in my equation.

And thanks for all your help. I think I'm starting to get this more, so hopefully this will be my last rewriting problem!
 

FAQ: Solving for b_1: Help Needed with 2A=h(b_{1}+b_{2})?

How do I solve for b1 in the equation 2A=h(b1+b2)?

To solve for b1, you will need to use algebraic principles to isolate the variable on one side of the equation. Start by distributing the h to the terms inside the parentheses, then combine like terms. Finally, divide both sides by the coefficient of b1 to get the value of b1.

Can I solve for b1 if both b1 and b2 have variables in them?

Yes, you can still solve for b1 even if it has variables in it. Just follow the same steps as you would for a regular algebraic equation. Remember to keep the variables on one side and constants on the other side when combining like terms.

Can I solve for b1 if I only have the value of h and not the value of A?

Yes, you can still solve for b1 if you only have the value of h. However, you will not get a specific value for b1, but rather an expression in terms of h and b2. This means that the value of b1 will depend on the value of b2.

What if the equation contains more than two variables, such as b1, b2, and b3?

If the equation has more than two variables, you will need to have the values of at least two variables to solve for the remaining ones. This means you will need to have the values of A, h, and one of the b variables to solve for the other b variables.

Is there a specific formula for solving equations with multiple variables, like the one given?

There is no specific formula for solving equations with multiple variables. The steps for solving these equations will depend on the specific equation given. However, the general principles of algebra, such as isolating the variable and combining like terms, can be applied to solve for the desired variable.

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