Solving for forces/reactions and moments in a complicated frame

In summary, to solve the problem, first find the vertical components of the reactions F and B by considering the entire system. Then, dismember the system to find the horizontal components. It is important to note that moments are free vectors and should be considered in all moment equations when dismembering the system.
  • #1
salman213
302
1
1.
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2. [tex]\sum[/tex]Maboutapoint
[tex]\sum[/tex]Fy
[tex]\sum[/tex]Fx




3. Well firstly i just looked at it as a whole to see if i can figure out any of the reactions at F or B. I am confused about where to and where not to apply that moment of 48 Nm which is replacing the force at A.

For example when I am taking the moment about point F when looking at the system as A WHOLE, should i take into consideration that 48 Nm in the moment equation?

When I am taking it about point E of the WHOLE SYSTEM i do not? or no matter what, I have to add 48 Nm in all moment equations that i make?

And then please telll me when I DISMEMBER the frame when I am looking at the member FCA, is that the only time i take that moment into consideration, or no matter which dismembered part I am looking at, I have to take that moment of 48 Nm at point A into consideration in the MOMENT equation I make?
pleasezzzzzz help
 
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  • #2
In order to solve this problem, simply find the vertical (y-components) of the reactions F and B, by using the whole body, dismember for finding the horizontal (x-components).

Remember: Moments are Free vectors unlike forces which are sliding vectors.
 
  • #3


I would first like to commend you for taking the time to analyze and understand this complicated frame. It is important to carefully consider all forces and moments in order to accurately solve for the reactions and moments in a frame.

To answer your first question, when taking the moment about point F, you do not need to consider the moment of 48 Nm at A. This is because the moment at A is already accounted for in the moment equation at F. Similarly, when taking the moment about point E, you do not need to consider the moment at A. This is because the forces and moments at A are already accounted for in the overall moment equation at E.

When dismembering the frame and looking at individual members, the moment of 48 Nm at A should only be considered for the specific member that it is acting on. For example, when looking at member FCA, you would include the moment of 48 Nm at A in the moment equation for that member. However, when looking at member FBE, the moment at A would not be included in the moment equation for that member.

It is important to always consider the specific forces and moments acting on each individual member when solving for reactions and moments in a complicated frame. This may require dismembering the frame and analyzing each member separately. I hope this helps clarify any confusion you may have had.
 

FAQ: Solving for forces/reactions and moments in a complicated frame

How do I determine the external forces acting on a complicated frame?

To determine the external forces on a complicated frame, you will need to draw a free body diagram of the entire frame. This will allow you to identify all the forces acting on the frame, including any external forces such as applied loads or reactions from supports. Once you have identified all the external forces, you can use equations of equilibrium to solve for the reactions and moments.

What are the equations of equilibrium and how do I use them?

The equations of equilibrium are Newton's laws of motion applied to a system in equilibrium. This means that the sum of all forces acting on the frame must equal zero, and the sum of all moments must also equal zero. To use these equations, you will need to set up a coordinate system and assign positive and negative directions for forces and moments. Then, you can plug in the known values and solve for the unknown reactions and moments.

How do I handle distributed loads on a complicated frame?

Distributed loads can be handled by breaking them down into smaller, concentrated loads. You can do this by finding the total magnitude of the distributed load and dividing it by the length or area over which it is distributed. Then, you can treat each concentrated load as a point load and apply the equations of equilibrium accordingly.

Can I use any point on a frame to calculate moments?

No, you cannot use any point on a frame to calculate moments. When solving for moments, it is important to choose a point where the moment arm is known or can be easily calculated. This will ensure that the moment is calculated correctly and accurately reflects the distribution of forces on the frame.

What do I do if my calculated reactions and moments do not add up to zero?

If your calculated reactions and moments do not add up to zero, it is likely due to rounding errors or inaccuracies in your calculations. Double check your work and make sure all units are consistent. You may also need to consider any assumptions or simplifications made in the analysis. If the discrepancy is significant, it may be necessary to reassess the problem and try a different approach.

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