Solving for h & k: No Solution?

  • Thread starter KevinL
  • Start date
In summary, the question asks for the values of h and k in which the given system of equations has no solution. The solution can be found by solving for x, y, and z in terms of k and h, without using matrices. This will help determine the values of h and k that result in no solution.
  • #1
KevinL
37
0

Homework Statement



Determine all values of h and k for which the system has no solution:

5x + 3y + 6z = -5
-6x - 7y - 4z = 9
-17x - 17y + hz = k

k =! ?
h = ?

The Attempt at a Solution



I googled the question and apparently most people solve this with a matrix, but we haven't gotten far enough in the class where we manipulate matrices or anything of the sort. Nor have we done an example of this in class. I am a bit clueless as to both what the question is asking and of course how to go about solving it.
 
Physics news on Phys.org
  • #2
That's a system of equations with 3 variables. So, if you don't want to solve it using matrices, simply solve for x, y, and z in terms of k and h, like you would solve a normal system of equations. At that point it will be easy to determine which values of h and k give no solution to the system.
 

FAQ: Solving for h & k: No Solution?

What does it mean when there is no solution for h and k?

When there is no solution for h and k, it means that the system of equations does not have a common point of intersection. In other words, there is no value for h and k that satisfies both equations simultaneously.

How do you know if a system of equations has no solution for h and k?

You can determine if a system of equations has no solution for h and k by graphing the two equations on the same coordinate plane. If the lines do not intersect, then there is no solution for h and k.

Can a system of equations have no solution for h and k and still be consistent?

No, a system of equations cannot have no solution for h and k and still be consistent. A consistent system means that there is at least one solution that satisfies all of the equations, but if there is no solution for h and k, then the system is inconsistent.

Can a system of equations have no solution for h and k and still be independent?

Yes, a system of equations can have no solution for h and k and still be independent. The independence of a system is determined by the number of equations and variables, not by the existence of a solution.

How can you solve for h and k if there is no solution?

If there is no solution for h and k, then there is no way to solve for specific values of h and k. However, you can still find the relationship between the variables by manipulating the equations algebraically. You can also use a graphing calculator to visualize the relationship between the equations.

Back
Top