Solving for Maximum Speed on a Theme Park Ride: Phys Unit 4 - Swings Question 6

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In summary, the two students in the queue are discussing the effects of increasing the size of a theme park ride. One student believes that the g-force would be the same, while the other believes that the g-force would be twice as great. Assuming that both students are correct, the g-force would be 3.
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jsmith613
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Homework Statement


Question 6:
http://www.xtremepapers.com/Edexcel/Advanced%20Level/Physics/2008%20Jan/6754_01_que_20080121.pdf

"On one type of theme park ride, a..."


Homework Equations





The Attempt at a Solution


So at the bottom of the loop the ride is at its fastest
GPE = KE
mgh = 0.5*m*v2
max speed = 18.8

The net force is mv2/r = Tension - mg

How do I continue?
 
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  • #2
jsmith613 said:
The net force is mv2/r = Tension - mg
Consider the forces on the rider. (Not tension, but what?)
 
  • #3
Doc Al said:
Consider the forces on the rider. (Not tension, but what?)

reaction force from seat?
 
  • #4
jsmith613 said:
reaction force from seat?
Right. The reaction or normal force from the seat.
 
  • #5
ok I think I am working on it...
 
  • #6
so
R = mv^2/r + mg
R/mg = g-force
g-force = 3
right?
 
  • #7
but the next question 6b) is

Two students in the queue are having a discussion.
A says: “If they made a new ride twice as big the g-force at the bottom would be
amazing!”
B says: “I think the g-force wouldn’t be any different.”
With reference to your calculation, explain which student is correct.

If we look at our equation r (radius) is clearly a factor
but the answer says B is correct>
how?
 
  • #8
or would this cancel out due to a higher max speed?
 
  • #9
jsmith613 said:
so
R = mv^2/r + mg
R/mg = g-force
g-force = 3
right?
Right.
 
  • #10
jsmith613 said:
If we look at our equation r (radius) is clearly a factor
but the answer says B is correct>
how?
mv2 also depends on the radius. Express that term in terms of the radius and see what happens.
 
  • #11
Doc Al said:
mv2 also depends on the radius. Express that term in terms of the radius and see what happens.

yes they then cancel out
so (2g+g)/g = g-force
3 = g-force
 
  • #12
jsmith613 said:
yes they then cancel out
so (2g+g)/g = g-force
3 = g-force
Good.
 

FAQ: Solving for Maximum Speed on a Theme Park Ride: Phys Unit 4 - Swings Question 6

What is maximum speed on a theme park ride?

The maximum speed on a theme park ride refers to the highest velocity that a rider will experience during the ride. This can vary depending on the type of ride and its design, but it is typically measured in miles per hour (mph) or meters per second (m/s).

How is maximum speed calculated on a theme park ride?

Maximum speed on a theme park ride is calculated using the equation v = √(2gh), where v is the velocity, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the ride. This equation takes into account the potential energy and kinetic energy of the rider at the highest point of the ride.

What factors affect the maximum speed on a theme park ride?

The maximum speed on a theme park ride can be affected by several factors, such as the height and angle of the ride, the type and amount of propulsion, and the presence of any friction or air resistance. The weight and position of the riders can also impact the maximum speed.

Is maximum speed the same throughout the entire ride?

No, maximum speed is not the same throughout the entire ride. As the ride progresses, the potential and kinetic energy of the riders will change, causing the velocity to fluctuate. However, the highest point of the ride will typically have the maximum speed.

How does the maximum speed of a theme park ride impact rider experience?

The maximum speed of a theme park ride can greatly impact rider experience. A higher maximum speed can create a more thrilling and intense experience, while a lower maximum speed may be more suitable for younger or more sensitive riders. The design and engineering of the ride will also play a role in determining the overall rider experience.

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