- #1
kashmirekat
- 30
- 1
Hello all,
I have two charges, q1 & q2, along a horizontal axis of length L. I supposed to determine the length at which another charge, Q, can be placed so that its net force is zero, other than infinitely away.
I'm using the equation:
F = kq1Q / r + kq2Q / r
-- > kq1Q / (L+x)^2 = -( kq2Q / x^2 ) where x is the distance the point is away from L.
I substitute my #s and I get the equation:
(8 / (l^2 + 2xL + x^2)) = -(2/x^2)
and then I get:
8x^2 = -2(L^2 + 2xL + x^2)
-4x^2 = L^2 + 2xL + x^2
0 = L^2 + 2xL + 5x^2
Is this right? I cannot seem to solve for x.
I thought I initially had it, but reworked through my math and realized I forgot to have 2q negative. What I initally got was:
L^2 + 2xL - 3x^2
I can solve that by 'unfoiling' easily, but, as I previously mentioned, the math isn't correct to get that equation.
Thank you for your help and have a wonderful day.
I have two charges, q1 & q2, along a horizontal axis of length L. I supposed to determine the length at which another charge, Q, can be placed so that its net force is zero, other than infinitely away.
I'm using the equation:
F = kq1Q / r + kq2Q / r
-- > kq1Q / (L+x)^2 = -( kq2Q / x^2 ) where x is the distance the point is away from L.
I substitute my #s and I get the equation:
(8 / (l^2 + 2xL + x^2)) = -(2/x^2)
and then I get:
8x^2 = -2(L^2 + 2xL + x^2)
-4x^2 = L^2 + 2xL + x^2
0 = L^2 + 2xL + 5x^2
Is this right? I cannot seem to solve for x.
I thought I initially had it, but reworked through my math and realized I forgot to have 2q negative. What I initally got was:
L^2 + 2xL - 3x^2
I can solve that by 'unfoiling' easily, but, as I previously mentioned, the math isn't correct to get that equation.
Thank you for your help and have a wonderful day.