Solving for Recurring Numbers: Techniques and Applications

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In summary, the technique used is to equalize it x multiply by 10^(the number of digits recuring) then take away the original number.
  • #1
FateMaster
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Hihi... I am stumped at this question... I know there is a techique in doing this question... But i forget oredi... Help please...


Express this recurring number at a fraction of a/b...
Recurring number ---> 0.1454545454545...

Plz explain to me the technique used... No calculators allowed... :-p
 
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  • #2
The general trick is to equalise it x multiply by 10^(the number of digits recuring) then take away the orriginal number.

Using your problem as an example.

x = 0.1454545454545...

2 digits are recurring so multiply it be 100

100x = 14.54545454545...

Take away the orriginal number:

100x - x = 14.54545454545... - 0.1454545454545...

Take this a digit at a time:

99x = 14.40000000000...

99x = 14.4

That should be a little easier to solve now :smile:
 
  • #3
Stupid me... :smile:

Thankx... lol... So its this easy...

Hehe... Thankx for your help mate... :blushing: :biggrin:
 
  • #4
Slightly different way:

Because there is that "1" before the recurring "45", first multiply by 10:

10x= 1.454545...

Now multiply that by 100: 1000 x= 145.454545... and subtract

1000x- 10x= 900x= 144 so x= 144/900

Of course, that gives exactly the same result.
 
  • #5
HallsofIvy said:
1000x- 10x= 900x= 144 so x= 144/900

Of course, that gives exactly the same result.

Oh, no. Minor snag here. 1000x - 10x = 990x. So the answer really is 144/990. :smile:

You may simplify 144/990, of course.
 
  • #6
I like the fact that there are many different ways for solving problems. Here's another method. Not that it is really different: it just differs slightly from all the others.

x = 0.1454545...
10x = 1.454545...

10x - 1 = 0.454545...

We can work out 0.454545... to be 45/99 (100z - z = 45).

10x - 1 = 45/99
10x = (99 + 45)/99
10x = 144/99
x = 144/990
 
  • #7
also can do it by "geometric series", really the same again, but done once for all:

i.e. .1 + .045454545...

is .1 Plus the geometric series with initial term a= .045 and ratio r= 1/100, so the sum

is a + ar + ar^2 +...= a/(1-r) i.e. .045/(99/100) = (4.5)/99, so the answer is

.1 + this, as before.

I really do not like this answera s the others's answers are more elementary. but at least it shows how to algebraize their methods.
 

FAQ: Solving for Recurring Numbers: Techniques and Applications

What are recurring numbers?

Recurring numbers are numbers that appear repeatedly in a sequence or pattern.

Why do recurring numbers occur?

Recurring numbers occur due to mathematical principles and patterns.

How can recurring numbers be identified?

Recurring numbers can be identified by looking for patterns in a sequence of numbers or by using mathematical formulas.

What is the significance of recurring numbers?

Recurring numbers can have symbolic or spiritual significance for some individuals, but they also have practical applications in math and science.

Can recurring numbers be predicted?

It is possible to predict recurring numbers by using mathematical formulas and patterns, but they can also occur randomly in nature.

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