Solving for the Reaction Force by taking Moment about a Point

  • #1
daisy7777
16
1
Homework Statement
The stiff-leg derrick used on ships is supported by a
ball-and-socket joint at D and two cables BA and BC. The
cables are attached to a smooth collar ring at B, which allows
rotation of the derrick about z axis. If the derrick supports a
crate having a mass of 200 kg, determine the tension in the
cables and the x, y, z components of reaction at D.
Relevant Equations
∑Fx=0; ∑Fy=0; ∑M=0; ∑Fz=0;
Screenshot 2024-10-21 143819.png
For this problem, I took the moment about point B to 'get rid' of the tension force in the cables BA and BC. By doing this, I figured I could solve for the x and y components of the reaction force at D. From there, I could solve for the tension in BA and BC in the x and y and then solve for Dz. However, I got the wrong answer doing this and when looking at a video they approached the problem by taking the moment at D and solving for the tension in both the cables from there. Was my approach wrong or did I simply make a mistake in my calculations?
 
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  • #2
Please share your work in a clear format (preferably using LaTeX Guide) ,and maybe we can figure out what happened. I have suspicion that you neglected the tensions and/or reaction at ##D## in the rigging attached to the mast when taking your moment about ##B##. In other words perhaps we should examine what you think is a FBD of the mast. Maybe you made no mistake in the physics and just have a math error (maybe position vector from ##B## to the tip of the boom). I can't tell.

There is nothing wrong with taking torques about ##B## in theory to get some equations. Maybe it's a shortcut ( I assume you think it is). It could be nothing special though too.
 
Last edited:

FAQ: Solving for the Reaction Force by taking Moment about a Point

What is the moment about a point in physics?

The moment about a point, also known as torque, is a measure of the rotational effect of a force applied at a distance from that point. It is calculated as the product of the force and the perpendicular distance from the line of action of the force to the point of rotation. Mathematically, it can be expressed as M = F × d, where M is the moment, F is the force, and d is the distance.

Why is it important to take moments about a point when solving for reaction forces?

Taking moments about a point simplifies the analysis of forces acting on a structure or object. By focusing on moments, we can eliminate certain unknown forces from the equations, making it easier to solve for the remaining unknowns. This method is particularly useful in static equilibrium problems, where the sum of moments and forces must equal zero.

How do you choose the point about which to take moments?

The choice of point for taking moments often depends on the configuration of the forces and the unknowns involved. A good strategy is to select a point where multiple forces act, especially where you want to eliminate unknown reaction forces. This can simplify calculations and help isolate specific variables in the problem.

What are the steps to solve for the reaction force using moments?

To solve for the reaction force using moments, follow these steps: 1) Identify all forces acting on the structure, including applied loads and support reactions. 2) Choose a point to take moments about, ensuring it simplifies the problem. 3) Write the moment equation, setting the sum of moments equal to zero. 4) Solve the moment equation for the unknown reaction force. 5) Use equilibrium equations (sum of vertical and horizontal forces) to find any additional unknowns if necessary.

What are common mistakes to avoid when taking moments about a point?

Common mistakes include forgetting to consider the direction of the moments (clockwise vs. counterclockwise), neglecting to account for all forces acting on the object, and incorrectly measuring distances. Additionally, failing to apply the correct sign convention for moments can lead to incorrect results, so it’s essential to be consistent in your approach.

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