- #1
yungman
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Homework Statement
This is not a home work, I actually make this problem up and work on it. I want to verify whether I am correct in the step and I need help to solve the final integration.
The question is:
Given a plastic circular ring radius = a with line charge density glued on it. The charge density around the ring is given as [tex]\lambda = \lambda_0\left | sin \left ( \frac { \theta}{2}\right )\right |[/tex]. Then the ring is place on the xy plane with the center at origin and spin at constant angular velocity [itex]\omega[/itex]. I want to find the scalar potential V and vector potential A at P(x_0,0,z_0).
Homework Equations
[tex] \vec R \;\hbox { is position vector pointing to P. } \vec w(\phi) \;\hbox { is position vector pointing to a point of the ring.}[/tex]
[tex] \phi = \theta + \omega t_r = \theta +\omega \left ( t-\frac {\eta}{c}\right ) \;,\; \vec R = \hat x_0 + \hat z z_0\;,\; \vec w (\phi) = \hat x a\;cos (\phi) + \hat y a\; sin(\phi) = \hat x a\;cos (\theta + \omega t_r ) + \hat y a\; sin(\theta + \omega t_r ) [/tex]
[tex] \vec v(\phi) = \vec w\;' (\phi) = -\hat x a\omega\;sin (\theta + \omega t_r ) + \hat y a\omega \; cos(\theta + \omega t_r ) [/tex]
[tex]V_{(\vec r,t)} = \frac {1}{4\pi \epsilon_0}\int \frac { \rho_{(\vec r\;',t_r)}}{\eta c -\vec{\eta} \cdot \vec v(\phi)} a d\phi \;\hbox { where }\;\vec {\eta} = \vec R - \vec w (\phi) = \hat x(x_0-acos\phi)-\hat y a sin\phi+\hat z z_0[/tex]
[tex]\vec{\eta} \;\hbox { is the vector from a point of interest on the plastic ring to point P.}[/tex]
[tex] \eta = \sqrt{(x_0-acos\phi)^2+a^2sin^2\phi + z_0^2} = \sqrt{(x_0^2+a^2 -2ax_0 cos\phi) + z_0^2} = c(t-t_r)[/tex]
[tex]\vec {\eta} \cdot \vec v(\phi) = -a\omega sin\phi(x_0-acos\phi)-a^2\omega cos\phi sin\phi = -a\omega x_0sin\phi = -a\omega x_0 sin \left ( \theta + \omega \left ( t- \frac {\eta}{c}\right ) \right )[/tex]
The Attempt at a Solution
[tex] V_{(\vec r,t)} = \frac {1}{4\pi \epsilon_0}\int \frac { \rho_{(\vec r\;',t_r)}}{\eta c -\vec{\eta} \cdot \vec v(\phi)} a d\phi = \frac {\lambda_0 c }{4\pi \epsilon_0}\int \frac {\left | sin \left ( \frac {\phi}{2}\right ) \right | }{c\sqrt{x_0^2 +a^2-2ax_0cos\phi+z^2} + a\omega x_0sin\phi} a d\phi [/tex]
The next step is to substitude [tex] \phi = \theta + \omega \left ( t- \frac {\eta}{c}\right ) \;\hbox { and }\; \eta = c(t-t_r) \;\hbox { to solve for }\; t_r \;\hbox { and }\; \phi[/tex]
I don't know an easy to solve for [itex]t_r \;\hbox { or } \phi[/itex] as I have both [itex] t_r \;\hbox { and } \; cos \phi[/itex] in the same equation.
Please check for me whether I am doing this correctly so far because I don't have the correct solution since I make up this problem. And also give me hints how to solve of t_r or \phi.
Thanks
Alan
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