Solving for x: log 3 (x^2 -5x+6) - log 2 (2-x) = 2

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In summary, the problem is to find the value of x in the equation log3(x2 - 5x + 6) - log2(2 -x) = 2. After attempting the solution, both parties arrived at the equation x2 - 5x + 6 = 9(2 - x)(1/log32). However, it is unclear how to solve for x in this equation.
  • #1
JoanF
17
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Homework Statement



Find x:

log 3 (x^2 -5x+6) - log 2 (2-x) = 2

Homework Equations





The Attempt at a Solution


I tried and got:
(3-x).[(2-x)^1-log 2 (3)] = 9

but I don't know how to get x here ...
 
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  • #2
JoanF said:

Homework Statement



Find x:

log 3 (x^2 -5x+6) - log 2 (2-x) = 2
Some clarification, please. Is this
log[3(x2 - 5x + 6)] - log[2(2 - x)] = 2

or
log3(x2 - 5x + 6) - log2(2 -x) = 2
?
JoanF said:

Homework Equations





The Attempt at a Solution


I tried and got:
(3-x).[(2-x)^1-log 2 (3)] = 9

but I don't know how to get x here ...
 
  • #3
Mark44 said:
Some clarification, please. Is this
log[3(x2 - 5x + 6)] - log[2(2 - x)] = 2

or
log3(x2 - 5x + 6) - log2(2 -x) = 2
?

it is log3(x2 - 5x + 6) - log2(2 -x) = 2
 
  • #4
Are you sure you have the problem written correctly? It's very messy with the two log bases. I got to x2 - 5x + 6 = 9(2 - x)(1/log32)
 
  • #5
Mark44 said:
Are you sure you have the problem written correctly? It's very messy with the two log bases. I got to x2 - 5x + 6 = 9(2 - x)(1/log32)

You got the same I got


Yes I'm sure ...
 

FAQ: Solving for x: log 3 (x^2 -5x+6) - log 2 (2-x) = 2

How do you solve for x in this equation?

To solve for x, we must first combine the logarithms using the quotient rule: log3((x2 - 5x + 6)/(2-x)) = 2. Then, we can rewrite the equation as 32 = (x2 - 5x + 6)/(2-x). From there, we can solve for x using algebraic methods.

What is the domain of this equation?

The domain of this equation is all real numbers except x = 2 and x = 3, since those values would make the logarithms undefined.

Can this equation be solved using a calculator?

Yes, this equation can be solved using a calculator by converting the logarithms to exponential form and using the inverse function on the calculator.

Are there any other ways to solve this equation?

Yes, this equation can also be solved by graphing the two sides of the equation and finding the points of intersection. However, this method may not give an exact solution.

What are the possible solutions for this equation?

The possible solutions for this equation are x = 1 and x = 6. These are the values that make the left and right sides of the equation equal.

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