Solving for Y in c=2x^2-xy+2y^2

  • MHB
  • Thread starter shle
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In summary, "solving for Y" in this equation means finding the value of Y that satisfies the equation c=2x^2-xy+2y^2. It is necessary to solve for Y in this equation in order to understand the relationship between the variables x and y and their effect on the value of c. The steps to solve for Y in this equation are to group the terms containing Y, factor out the common factor of Y, and use the quadratic formula or other methods. This equation can have more than one solution for Y, but it may also have no real solutions. Solving for Y in this equation can be applied in various real-world situations, such as calculating projectile trajectories, determining optimal production levels, and
  • #1
shle
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Hi, I am trying to solve for Y in the equation:

c = 2x^2 - xy + 2y^2

Thank you!
 
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  • #2
shle said:
Hi, I am trying to solve for Y in the equation:

c = 2x^2 - xy + 2y^2

Thank you!

It's a quadratic in $y$. Do you know how to solve such problems?
 
  • #3
Google "The quadratic formula" or "completeing the square"
 

FAQ: Solving for Y in c=2x^2-xy+2y^2

What is the meaning of "solving for Y" in this equation?

When we say "solving for Y" in this equation, it means finding the value of Y that makes the equation true. In other words, we are trying to find the value of Y that satisfies the equation c=2x^2-xy+2y^2.

Why is it necessary to solve for Y in this equation?

Solving for Y in this equation allows us to find the relationship between the variables x and y. It also helps us to understand how changes in the values of x and y affect the value of c.

What are the steps to solve for Y in this equation?

The steps to solve for Y in this equation are as follows:

  1. Group the terms containing Y on one side of the equation.
  2. Factor out the common factor of Y from the grouped terms.
  3. Use the quadratic formula or other methods to solve for Y.

Can this equation have more than one solution for Y?

Yes, this equation can have more than one solution for Y. This is because it is a second-degree equation and can have two solutions. However, it may also have no real solutions depending on the values of x and c.

How can solving for Y in this equation be applied in real-world situations?

Solving for Y in this equation can be applied in various real-world situations, such as calculating the trajectory of a projectile, determining the optimal level of production in economics, or finding the maximum profit in business. It can also be used to model and analyze natural phenomena in fields like physics and biology.

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