- #1
Miike012
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Homework Statement
if a/b = c/d = e/f
then show that...
(a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) = ace/bdf
Homework Equations
1.I understand how to prove it but I don't understand algebraically how they got from
a/b = c/d = e/f to... (a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3)
( or is this irrelevant and what I should focus on is the proving the theorem?)
2. second I don't understnad how (a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) = ace/bdf?
the numerator does not simplify into the denominator UNLESS...
because a/b = c/d = e/f
(a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) could also equal (k^4 + 2k^3 - 3k^4)/(k^4 + 2k^3 - 3k^4) = 1
and ace/bdf could equal k^3/k^3 = 1
therefore 1=1 is true?