- #1
Pietjuh
- 76
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Suppose we have a commutative ring R and ideals I and J of R such that I + J = R. I have to show that there exist positive numbers m,n such that I^m + J^n = R.
I think the trick is just to show that I^m + J^m contains 1. Because I + J = R, I+J contains 1 so there exist i in I and j in J such that i + j = 1. Now I have to find a a^m in I^m and a b^n in J^n such that a^m + b^n = 1.
I tried a lot of things but none of them seemed to work :(
Can anyone give me a hint how to find these a^m and b^n ?
Thanks in advance
I think the trick is just to show that I^m + J^m contains 1. Because I + J = R, I+J contains 1 so there exist i in I and j in J such that i + j = 1. Now I have to find a a^m in I^m and a b^n in J^n such that a^m + b^n = 1.
I tried a lot of things but none of them seemed to work :(
Can anyone give me a hint how to find these a^m and b^n ?
Thanks in advance