Solving Implicit Functions: x(u^2)+v=y^3, 2yu-x(v^3)=4x

In summary, the problem involves finding the derivatives du/dx and dv/dx for the given equations. The method for solving this problem is to differentiate the equations implicitly and solve for the derivatives from the resulting equations. It is assumed that u and v are both functions of x and y. The final answers for a) and b) are given as ((v^3)-3x(u^2)(v^2)+4)/(6(x^2)-u(v^2)+2y) and (2x(u^2)+3(y^3))/(3(x^2)u(v^2)+y) respectively.
  • #1
mj1357
5
0

Homework Statement



If x(u^2) + v=(y^3), 2yu - x(v^3)=4x. Find a) du/dx and b) dv/dx

Homework Equations





The Attempt at a Solution



Not sure if I am supposed to differentiate as is, or try and write u and v as functions of x and y. The answer is supposed to be:

a) ((v^3)-3x(u^2)(v^2)+4)/(6(x^2)-u(v^2)+2y)

b) (2x(u^2)+3(y^3))/(3(x^2)u(v^2)+y)
 
Physics news on Phys.org
  • #2
so i assume v & u are both functions of x & y? ie u=u(x,y), v=v(x,y)

i would attempt to implicitly differentiate both equations, which will give you 2 eqns containing du/dx and dv/dx, then use them to solve for each
 

FAQ: Solving Implicit Functions: x(u^2)+v=y^3, 2yu-x(v^3)=4x

How do you solve an implicit function?

Solving an implicit function requires isolating one variable in terms of the others, using algebraic manipulation and/or substitution.

What is the difference between an implicit and explicit function?

An explicit function has one variable explicitly defined in terms of the others, while an implicit function does not have any one variable explicitly defined.

What is the purpose of solving implicit functions?

Solving implicit functions allows us to find the relationship between variables and understand the behavior of a system. It is also useful in solving real-world problems in fields such as physics, engineering, and economics.

What are some strategies for solving implicit functions?

Some strategies for solving implicit functions include using algebraic manipulation, substitution, graphing, and numerical methods such as Newton's method or the secant method.

Can implicit functions have multiple solutions?

Yes, implicit functions can have multiple solutions. This is because they do not have one variable explicitly defined, so there can be multiple combinations of variables that satisfy the equation.

Back
Top