- #1
- 2,194
- 198
I'm wondering how to solve an inequality like this:
x + 3^x < 4
I can see that it is the sum of the identity function and an exponential function. I can see that it is monotone increasing because each of those is. I therefore know that it crosses y=4 at only one x-value (call it x_1) and I know the solution will be x < x_1.
So I need to solve for x in x + 3^x = 4, how would I do that? I see I could draw the graph and read off the value, which I can see is x_1 = 1, but is there a way to calculate it?
Thank you for any clarification.
x + 3^x < 4
I can see that it is the sum of the identity function and an exponential function. I can see that it is monotone increasing because each of those is. I therefore know that it crosses y=4 at only one x-value (call it x_1) and I know the solution will be x < x_1.
So I need to solve for x in x + 3^x = 4, how would I do that? I see I could draw the graph and read off the value, which I can see is x_1 = 1, but is there a way to calculate it?
Thank you for any clarification.