Solving Integrals using summations

In summary, solving integrals using summations involves dividing the interval of integration into smaller subintervals and finding the sum of areas of rectangles or trapezoids within each subinterval. There are different methods for this, such as the Left Riemann Sum, Right Riemann Sum, Midpoint Riemann Sum, and Trapezoidal Rule. Definite integrals have specific limits of integration, while indefinite integrals do not. Integrals with variable limits of integration can be solved using summations, but the accuracy of the approximation depends on the number of subintervals and the smoothness of the function. However, this method may not always provide an exact solution and some integrals may be difficult to solve using summations
  • #1
Amad27
412
1

Homework Statement


Many places I have seen when solving integrals you change a lot of it into sums.

http://math.stackexchange.com/quest...dfrac-tan-x1m2-tan2x-mathrmdx/1006076#1006076

Is just an example.

So in general, how do you solve integrals (CLOSED FORM) by using series?

Thanks!

(for example integrate [itex]\displaystyle \int_{0}^{4\pi} \sin(x) dx[/itex] using SERIES)?

Thanks!

Homework Equations



[itex]\sin(x) [/itex]

The Attempt at a Solution


[/B]
I am a beginner, with no expertise in this area, so I asked the question. I don't know any methods to start with. Any help will be appreciated.
 
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  • #2
Do you know what the MacLaurin series (Taylor series centered on x= 0) is for sin(x)?
 
  • #3
Tonelli's theorem says that if [itex]f_{n}(x) \geq 0 \text{ } \forall n, x[/itex], then we can interchange the sum and the integral as follows:

[tex]\sum \int f_{n}(x) dx = \int \sum f_{n}(x) dx.[/tex]

For general [itex]f_n,[/itex] Fubini's theorem says that if either [itex]\int \sum |f_n|[/itex] or [itex]\sum \int |f_n|[/itex] converge, then [itex]\int \sum f_n = \sum \int f_n.[/itex]
 
Last edited:
  • #4
Amad27,
When you write a LaTeX expression, please use the correct tags. For itex, the closing tag is /itex, not \itex (in brackets). I fixed your post here and the LaTeX in your other post about limits.

You can check that what you have done is correctly formatted by clicking the PREVIEW button.
 

FAQ: Solving Integrals using summations

How do I solve an integral using summation?

To solve an integral using summation, you first need to understand the concept of Riemann sums. This involves dividing the interval of integration into smaller subintervals and finding the sum of the areas of rectangles within each subinterval. As the number of subintervals increases, the Riemann sum becomes closer to the actual value of the integral.

What is the difference between a definite and indefinite integral?

A definite integral has specific limits of integration, whereas an indefinite integral does not. In other words, a definite integral gives a numerical value, while an indefinite integral gives a general function. Solving integrals using summations is typically used for definite integrals.

What are the different methods for solving integrals using summations?

The most common methods for solving integrals using summations include the Left Riemann Sum, Right Riemann Sum, Midpoint Riemann Sum, and Trapezoidal Rule. Each method involves a slightly different approach to dividing the interval and calculating the areas of rectangles or trapezoids.

Can integrals with variable limits of integration be solved using summations?

Yes, integrals with variable limits of integration can be solved using summations. However, the number of subintervals and the width of each subinterval will need to be determined based on the specific limits of integration in order to accurately approximate the integral.

Are there any limitations to solving integrals using summations?

Solving integrals using summations is a numerical method, so it may not always provide an exact solution. The accuracy of the approximation depends on the number of subintervals used and the smoothness of the function being integrated. Additionally, some integrals may be difficult to solve using summations due to their complexity or lack of a closed form solution.

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