Solving Intractable Integral: \frac{1}{(1+a cos(\theta - \phi))^2}

  • Thread starter NoobixCube
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In summary, the conversation revolved around finding a solution for the integral \int \frac{1}{(1+a cos(\theta - \phi))^2} d\theta where a is a constant. Suggestions were made to expand the denominator and use the derivative of tan^{-1}{(\theta + \phi)} to simplify the solution, but it was ultimately solved by considering the substitution \theta- \phi=t. Some users suggested using software like Mathematica to solve the integral, while others mentioned using numerical methods or defining it as a new function. Additionally, someone recommended looking into elliptical integrals for more information. Overall, the conversation ended with the suggestion to use the aforementioned substitution for an easier solution.
  • #36
If you mean elementary anti derivative, then a) If you have limits of integration, numerical methods, or b) Define it as a new function ! =]
 
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  • #37
Thanks for taking the time ice109 :smile:
 
  • #38
You can solve this integral by considering it after the simple substitution:

[tex]\theta- \phi=t[/tex]

as:

[tex]\int\frac{dt}{(1+acos(t))^2}[/tex]

Now use the substitution:

[tex]1+acos(t)=\frac{1-a^2}{1-acos(t)}[/tex]

You will easily arrive at the solution.

Take a look at an older post of me where I explain this substitution a bit more:

https://www.physicsforums.com/showthread.php?t=204639

Hope this helps.
 

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