- #1
BobMarly
- 19
- 0
Not sure of solution for IVP
(x^2)*y"+4*x*y'+4*y=0
y(1)=1 y'(1)=2
Start with r(r-1)+4r+4=0
then (r^2)+3r+4=0
get (-3+/-7i)/2
Leads to y=C(1)e^(-3t/2)cos(7t/2)+C(2)e^(-3t/2)sin(7t/2)
More y'=... one large formula
Am I on the correct track, is there something I missed, or is there a shortcut here
it seems that by putting in IV's, it doesn't lead to anything clean
Homework Statement
(x^2)*y"+4*x*y'+4*y=0
y(1)=1 y'(1)=2
Homework Equations
Start with r(r-1)+4r+4=0
then (r^2)+3r+4=0
get (-3+/-7i)/2
The Attempt at a Solution
Leads to y=C(1)e^(-3t/2)cos(7t/2)+C(2)e^(-3t/2)sin(7t/2)
More y'=... one large formula
Am I on the correct track, is there something I missed, or is there a shortcut here
it seems that by putting in IV's, it doesn't lead to anything clean
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