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nblu
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Q: The average alcohol-free driver requires about 0.8 s to apply the brakes
after seeing an emergency. Calculate the distance traveled after seeing the emergency
before applying the brakes.
with the question, the given speed is 17 m/s and t = 0.8.
at first, i used d =vt equation to find the distance, however,
when i read through the question again, i had a feeling that it's not right.
my first answer was d=14m, but it just doesn't look correct.
i was thinking of finding the acceleration then use v[tex]^{2}_{f}[/tex]=v[tex]^{2}_{i}[/tex] +2a[tex]\Delta[/tex]d
to solve for d, OR, use this equation, [tex]\Delta[/tex]d=1/2(v[tex]_{1}[/tex]+v[tex]_{2}[/tex])[tex]\Delta[/tex]t, without
even having to find the acceleration.
one part of my knowledge tells me that i don't need acceleration to do this question
because this is about "before" applying the break.
its confusing me..
any help would be greatly appreciated.
thank you
after seeing an emergency. Calculate the distance traveled after seeing the emergency
before applying the brakes.
with the question, the given speed is 17 m/s and t = 0.8.
at first, i used d =vt equation to find the distance, however,
when i read through the question again, i had a feeling that it's not right.
my first answer was d=14m, but it just doesn't look correct.
i was thinking of finding the acceleration then use v[tex]^{2}_{f}[/tex]=v[tex]^{2}_{i}[/tex] +2a[tex]\Delta[/tex]d
to solve for d, OR, use this equation, [tex]\Delta[/tex]d=1/2(v[tex]_{1}[/tex]+v[tex]_{2}[/tex])[tex]\Delta[/tex]t, without
even having to find the acceleration.
one part of my knowledge tells me that i don't need acceleration to do this question
because this is about "before" applying the break.
its confusing me..
any help would be greatly appreciated.
thank you
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