- #1
BigCountry
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Good Morning,
Just checking my work, your help would be much appreciated.
A bullet is fired vertically into the air at a speed of 512 m/s.
a) To what maximum height will the bullet does the bullet go?
b) How much time passes before the bullet stops rising?
c) What is the velocity of the bullet after 60 seconds?
My Answers:
a)
Vi = 0, Vf = 512, g = -9.8, find d
Vf^2 = Vi^2 + 2ad
512^2 = 2(-9.8)d
262144 = (-19.6)d
262144/(-19.6) = d
13375 m = d
b)
Vi = 0, Vf = 512, g = -9.8, find t
Vf = Vi + at
512 = 0 + (-9.8)t
512/(-9.8) = t
52.24 Secs = t
c)
Vi = 0, g = -9.8, t = 8, find Vf
Vf = Vi + at
Vf = 9.8 * 8
Vf = 78.4 or 78 m/s^2
Thank You
Just checking my work, your help would be much appreciated.
A bullet is fired vertically into the air at a speed of 512 m/s.
a) To what maximum height will the bullet does the bullet go?
b) How much time passes before the bullet stops rising?
c) What is the velocity of the bullet after 60 seconds?
My Answers:
a)
Vi = 0, Vf = 512, g = -9.8, find d
Vf^2 = Vi^2 + 2ad
512^2 = 2(-9.8)d
262144 = (-19.6)d
262144/(-19.6) = d
13375 m = d
b)
Vi = 0, Vf = 512, g = -9.8, find t
Vf = Vi + at
512 = 0 + (-9.8)t
512/(-9.8) = t
52.24 Secs = t
c)
Vi = 0, g = -9.8, t = 8, find Vf
Vf = Vi + at
Vf = 9.8 * 8
Vf = 78.4 or 78 m/s^2
Thank You