Solving Kinematics Problems: Maximum Height, Time, and Velocity Calculations

  • Thread starter BigCountry
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In summary, the bullet is fired vertically into the air at a speed of 512 m/s. It reaches a maximum height of 13375 meters and takes 52.24 seconds to stop rising. After 60 seconds, its velocity is -78.4 m/s or 78.4 m/s downwards. Accuracy is important in calculations.
  • #1
BigCountry
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Good Morning,

Just checking my work, your help would be much appreciated.

A bullet is fired vertically into the air at a speed of 512 m/s.

a) To what maximum height will the bullet does the bullet go?

b) How much time passes before the bullet stops rising?

c) What is the velocity of the bullet after 60 seconds?

My Answers:

a)

Vi = 0, Vf = 512, g = -9.8, find d

Vf^2 = Vi^2 + 2ad
512^2 = 2(-9.8)d
262144 = (-19.6)d
262144/(-19.6) = d
13375 m = d

:smile:


b)

Vi = 0, Vf = 512, g = -9.8, find t

Vf = Vi + at
512 = 0 + (-9.8)t
512/(-9.8) = t
52.24 Secs = t

c)

Vi = 0, g = -9.8, t = 8, find Vf

Vf = Vi + at
Vf = 9.8 * 8
Vf = 78.4 or 78 m/s^2

Thank You
 
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  • #2
All correct. :smile:
Better not use t=8s in c), but the more accurate 7.76s. Makes a difference of 2m, but who's counting.
 
  • #3
BigCountry said:
My Answers:

a)

Vi = 0, Vf = 512, g = -9.8, find d

Vf^2 = Vi^2 + 2ad
512^2 = 2(-9.8)d
262144 = (-19.6)d
262144/(-19.6) = d
13375 m = d
I'd say that Vi = 512 m/s, Vf = 0. (This way you won't have to ignore any strange minus signs. :wink: ) Otherwise, looks good.

b)

Vi = 0, Vf = 512, g = -9.8, find t

Vf = Vi + at
512 = 0 + (-9.8)t
512/(-9.8) = t
52.24 Secs = t
Again: Vi = 512 m/s, Vf = 0. Otherwise, looks good.

c)

Vi = 0, g = -9.8, t = 8, find Vf

Vf = Vi + at
Vf = 9.8 * 8
Vf = 78.4 or 78 m/s^2
Huh? t = 60 s, not 8. (Again: Vi = 512 m/s) Note: Signs count!

(Note: Now I see what you did for question c: You started from the top. Good! But take Galileo's advice about accuracy. Note that the velocity is negative.)
 
Last edited:
  • #4
Thanks Galileo!

Much appreciated!
 

Related to Solving Kinematics Problems: Maximum Height, Time, and Velocity Calculations

1. What is the formula for calculating maximum height in kinematics?

The formula for calculating maximum height in kinematics is h = (v02sin2θ)/(2g), where v0 is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.

2. How do you calculate time in kinematics?

To calculate time in kinematics, you can use the formula t = (vf - v0)/a, where vf is the final velocity, v0 is the initial velocity, and a is the acceleration.

3. Can you explain the concept of velocity in kinematics?

In kinematics, velocity is the rate of change of an object's position with respect to time. It is a vector quantity, meaning it has both magnitude and direction. Velocity can be calculated by dividing the displacement of an object by the time it takes to travel that distance.

4. What is the difference between average velocity and instantaneous velocity in kinematics?

Average velocity is the total displacement of an object divided by the total time taken, while instantaneous velocity is the velocity of an object at a specific moment in time. Average velocity gives an overall picture of an object's motion, while instantaneous velocity gives more specific information about its motion at a particular point.

5. How can you use kinematics to solve real-world problems?

Kinematics can be used to solve a variety of real-world problems, such as calculating the trajectory of a projectile, determining the speed of a moving object, or predicting the position of an object at a given time. By using the formulas for displacement, velocity, and acceleration, you can analyze the motion of objects and make predictions about their behavior in the physical world.

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