MHB Solving $\lim_{{x}\to{0}} lnx \cdot x$: Overview & Proofs

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The limit $\lim_{{x}\to{0}} \ln x \cdot x$ involves $x$ approaching 0 while $\ln x$ approaches $-\infty$. The reasoning suggests that $x$ approaches 0 faster than $\ln x$ approaches $-\infty$, leading to the conclusion that the limit is 0. To prove this, the expression can be rewritten as $L=\lim_{x\to0}\left(\frac{\ln(x)}{\frac{1}{x}}\right)$, which allows for the application of L'Hôpital's Rule. This method confirms that the limit indeed evaluates to 0. The final conclusion is that the limit is 0.
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I have

$\lim_{{x}\to{0}} lnx \cdot x$

$x$ approaches 0, and $lnx$ approaches $\infty$.

How can I reason about this.

I suppose $x$ approaches 0 more quickly than $lnx$ approaches $\infty$ , therefore it is zero. Is this accurate? How can I prove this.
 
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I would write it as:

$$L=\lim_{x\to0}\left(\frac{\ln(x)}{\dfrac{1}{x}}\right)$$
 
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