- #1
Iron_Brute
- 19
- 0
Two basic limit problems just solve the limit if it exists. I know the answers but I don't understand why the answers are what they are.
1.) lim (x^2-x-2) / (x-2)^2
x->2
2.) lim ((1/x)-(1/2)) / (x-2)
x->2
Answers were:
1.) DNE
2.) -1/4
I kind of understand that the first problem the denominator would be 0, but I thought if you factored the top and bottom you could find the limit of (x+1).
The second one I am completely stuck the only thing I could think to do was use the division rule but I would still have 0 for the denominator. If anyone could explain this it would be a big help.
1.) lim (x^2-x-2) / (x-2)^2
x->2
2.) lim ((1/x)-(1/2)) / (x-2)
x->2
Answers were:
1.) DNE
2.) -1/4
I kind of understand that the first problem the denominator would be 0, but I thought if you factored the top and bottom you could find the limit of (x+1).
The second one I am completely stuck the only thing I could think to do was use the division rule but I would still have 0 for the denominator. If anyone could explain this it would be a big help.