mathsheadache said:If I have a similar question \(\displaystyle \frac{y}{5}+\frac{7}{20}=\frac{5-y}{4}\) should I go about the same process as the http://mathhelpboards.com/pre-algebra-algebra-2/solve-following-equation-12605.html? Try and cancel out the denominators of 5, 20 and 4? Which would be 20? So times the equation by 20?
ineedhelpnow said:yep and that would get rid of the denominator 4y+7=5(5-y)
mathsheadache said:Understood that part, so from here expand to get \(\displaystyle 4y+7=25-5y?\) Move like terms together so, \(\displaystyle 4y+5y=25-7?\) \(\displaystyle \therefore9y=18\implies y=2?! \) :D
A linear equation is an algebraic equation that contains only variables with a degree of 1. It can be written in the form y = mx + b, where m is the slope and b is the y-intercept.
To solve a linear equation for y, you need to isolate the variable y on one side of the equation. This can be achieved by using algebraic operations such as addition, subtraction, multiplication, and division. Once y is isolated, the resulting equation will be in the form y = mx + b, where m and b can be determined.
Solving a linear equation involves finding the value of the variable(s) in the equation, while graphing a linear equation involves plotting the equation on a coordinate plane to visualize the relationship between the variables. Solving a linear equation results in a single solution, while graphing a linear equation shows all possible solutions.
To check if a solution to a linear equation is correct, substitute the values of the variables into the equation and simplify. If the resulting equation is true, then the solution is correct. If not, then the solution is incorrect.
Linear equations are widely used in various fields such as finance, engineering, and science. They are used to model and solve real-life problems involving relationships between variables, such as calculating interest rates, predicting population growth, and determining the trajectory of a projectile.