- #1
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Hi, I am having a little trouble solving a linear equation:
[tex] y' cosx = ysinx + 2x [/tex]
I translated it into standard y' + P(x)y= Q(x) format as
[tex]y' - ytanx = 2x/cosx [/tex]
then I needed an integrating factor, so I used
[tex]I(x)=e^{-\int tanx\:dx} = cosx[/tex]
when I multiply this to both sides of [tex]y' - ytanx = 2x/cosx [/tex]
it doesn't seem to do much good. I just get back to where I started, and I am not seeing anything that will wrap into a nice neat little derivative on the LHS.
Can you show me where I am going wrong? Thanks!
[tex] y' cosx = ysinx + 2x [/tex]
I translated it into standard y' + P(x)y= Q(x) format as
[tex]y' - ytanx = 2x/cosx [/tex]
then I needed an integrating factor, so I used
[tex]I(x)=e^{-\int tanx\:dx} = cosx[/tex]
when I multiply this to both sides of [tex]y' - ytanx = 2x/cosx [/tex]
it doesn't seem to do much good. I just get back to where I started, and I am not seeing anything that will wrap into a nice neat little derivative on the LHS.
Can you show me where I am going wrong? Thanks!