Solving Math Formulaes: X/5 to X-5 with Lagranges Equation

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In summary, the conversation discusses finding good mathematics formula books and converting expressions involving X/5 into other forms.
  • #1
storoi1990
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Homework Statement



Does anybody know of some good mathematics formula books?

i am currently stuck with: X/5

Can i turn this into something else, like: X-5?

i got this from the equation: X+ 5y = 3000

then: 5y = 3000 - x

y = 600 - x/5

Now i have to put this into a Lagranges equation:

f(x,y) = 100x^1/2 + 100y^1/2-1000

wich i now get: 100x^1/2 + 100 (600-x/5)^1/2-1000

how do i solve this?


Homework Equations





The Attempt at a Solution

 
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  • #2
What, exactly are you trying to do? You talk about "solving" an equation, but you have no equation. IF what you have is set equal to something, typically, what you would need to do is isolate the square roots on opposite sides of the equals sign and square both sides. You probably will need to square twice.
 
  • #3
What you're asking for doesn't exist.
storoi1990 said:
Does anybody know of some good mathematics formula books?
i am currently stuck with: X/5
Can i turn this into something else, like: X-5?
About the only thing you can do with x/5 is to write it as a product: x * (1/5). About the only thing you can do with x - 5 is to write it as a sum: x + (-5). You can always write a quotient of two expressions as a product of one of them times the reciprocal of the other, and you can always write a sum of two expressions as one of them plus the additive inverse of the other, but that's about it.
 

FAQ: Solving Math Formulaes: X/5 to X-5 with Lagranges Equation

How do you use Lagrange's equation to solve math formulas?

Lagrange's equation is a mathematical tool used to find the extrema (maximum or minimum) of a function. To use it to solve a math formula, you must first write the formula as a function of a single variable, typically denoted by x. Next, take the derivative of the function and set it equal to 0 to find critical points. Finally, plug the critical points into the second derivative of the function to determine if they are maxima or minima.

Can Lagrange's equation be used for any type of math formula?

Yes, Lagrange's equation can be used to find the extrema of any type of function, whether it is linear, quadratic, exponential, or any other type of formula. However, it may not always be the most efficient method and there may be other techniques that are more suitable for certain types of formulas.

Are there any limitations to using Lagrange's equation?

One limitation of Lagrange's equation is that it can only find extrema for functions with a single variable. Additionally, it may not always yield a solution for more complex formulas, and in those cases, other methods may need to be used.

How do you know if a critical point found using Lagrange's equation is a maximum or minimum?

To determine if a critical point is a maximum or minimum, you must plug it into the second derivative of the function. If the second derivative is positive, the critical point is a minimum, and if it is negative, the critical point is a maximum. If the second derivative is 0, then the test is inconclusive and further analysis may be needed.

Can Lagrange's equation be used to solve equations with multiple variables?

No, Lagrange's equation can only be used for functions with a single variable. If you have an equation with multiple variables, you may need to use other techniques such as partial derivatives or substitution to solve for the extrema.

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