- #1
23scadoo
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Here is a question that i have on a test review and neither the book or the teachers examples are any help.
If 200mL of 0.800 molar HClO is added to 400mL of 0.200 molar Ba(OH)2 solution, the resulting solution will be ________M in Ba(ClO4)2.
I know that the answer is 0.133M
i know that the balanced equation is:
2HClO4 + Ba(OH)2 ----> Ba(ClO4)2 + 2H2O
The steps that she has given us to do are:
1. balance equation
2. reaction ration
3. Start
4. Change
5. After reaction
6. Final Volume of Solution
7. Molarity
If anyone could explain how this problem is worked i would be greatly appreciative.
If 200mL of 0.800 molar HClO is added to 400mL of 0.200 molar Ba(OH)2 solution, the resulting solution will be ________M in Ba(ClO4)2.
I know that the answer is 0.133M
i know that the balanced equation is:
2HClO4 + Ba(OH)2 ----> Ba(ClO4)2 + 2H2O
The steps that she has given us to do are:
1. balance equation
2. reaction ration
3. Start
4. Change
5. After reaction
6. Final Volume of Solution
7. Molarity
If anyone could explain how this problem is worked i would be greatly appreciative.