Solving ODE: 2y(1+x^2√y)dx + x(2+x^2√y)dy = 0 | Step-by-Step Guide

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In summary, the conversation discusses a substitution method for solving a differential equation and differentiating it correctly. It then suggests grouping the terms into perfect differentials to simplify the equation.
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Homework Statement


[tex]2y(1+x^2\sqrt{y})dx + x(2+x^2\sqrt{y})dy = 0[/tex]

The Attempt at a Solution


well, I substituted x^2√y=u but then when I tried to differentiate it I understood it would be so hard. Please check and see if I've differentiated it correctly:

√y = u/x^2 -> y = u^2.x^-4 -> dy/dx = 2u.u'x^(-4) - 4x^(-5).u^2
Is that correct? if yes, then I think I've just made the problem harder. how can I solve that ODE?
 
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  • #2
It is correct. Substitute for y and y' in the original equation, simplify and arrange: it is a separable ODE.

ehild
 
  • #3
You could try grouping the terms into perfect differentials. For example, 2 y dx + 2 x dy = 2 d(xy). The other two terms can be written similarly as d(something) . Then write u = xy and v = something and it is a simple linear ODE.
 

FAQ: Solving ODE: 2y(1+x^2√y)dx + x(2+x^2√y)dy = 0 | Step-by-Step Guide

How do I determine the order of an ODE?

The order of an ODE is determined by the highest derivative present in the equation. For example, if the equation contains only first derivatives, it is a first-order ODE. If it contains second derivatives, it is a second-order ODE, and so on.

What methods can I use to solve an ODE?

There are several methods that can be used to solve an ODE, including separation of variables, substitution, and integrating factors. The choice of method depends on the specific form of the ODE and the initial conditions given. It is important to select the most appropriate method for the given problem.

How do I find the general solution to an ODE?

The general solution to an ODE is the most general form of the solution that satisfies the equation. It typically includes one or more arbitrary constants. To find the general solution, one must use the chosen method of solving the ODE and then include the arbitrary constants in the final solution.

What are initial conditions and why are they important in solving an ODE?

Initial conditions are conditions given at a specific point or time that allow for the determination of the arbitrary constants in the general solution. They are important because they help to find the specific solution that satisfies both the ODE and the given initial conditions.

How do I know if my solution to an ODE is correct?

To check the correctness of a solution to an ODE, one can plug the solution back into the original equation and see if it satisfies the equation. Additionally, the solution should also satisfy any given initial conditions. If both of these conditions are met, the solution is considered correct.

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