- #1
Juggler123
- 83
- 0
I'm finding a solution to and ODE using a Frobenius form solution, I have worked through the question and have ended up with a recurrence of the form;
a(k) = -2/(2k-1) a(k-1)
I'm trying to find a general reccurence in terms of a(0) but am finding it a bit difficult, I know it has to have a (2n-1)! term on the bottom of the fraction and a (-2)^(n) term on top but I'm a bit stuck as to where to go after this.
Sorry I haven't Latex-ed anything, I don't know how!
Any help would be fantastic, thanks.
a(k) = -2/(2k-1) a(k-1)
I'm trying to find a general reccurence in terms of a(0) but am finding it a bit difficult, I know it has to have a (2n-1)! term on the bottom of the fraction and a (-2)^(n) term on top but I'm a bit stuck as to where to go after this.
Sorry I haven't Latex-ed anything, I don't know how!
Any help would be fantastic, thanks.