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BusyEarning
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i know this problem is posted on this forum somwhere else but i can't quite understand thanks in advance
A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. If
the mass is displaced by 10 mm from its equilibrium position and
released, for the resulting vibration, calculate:
the maximum velocity of the mass during the vibration
F=kl
so far i am thinking that i need to use hookes law as follows so i can get the amplitude
F=k(l+x)
F= mg = 0.3 kg x 9.81 = 2.94 N
k = 200 Nm-1
l = static spring reflection = 2.94/200 = 0.01
x = displacement due to external force = 10mm
so the amplitude would be l + x = 10.01mm?
do i need to take into account the extra extension when attempting the solution or is it just f/k =l
or do i need to use f/k = l + x to calculate the amplitude
any help would be appriciated
Thanks
Homework Statement
A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. If
the mass is displaced by 10 mm from its equilibrium position and
released, for the resulting vibration, calculate:
the maximum velocity of the mass during the vibration
Homework Equations
F=kl
The Attempt at a Solution
so far i am thinking that i need to use hookes law as follows so i can get the amplitude
F=k(l+x)
F= mg = 0.3 kg x 9.81 = 2.94 N
k = 200 Nm-1
l = static spring reflection = 2.94/200 = 0.01
x = displacement due to external force = 10mm
so the amplitude would be l + x = 10.01mm?
do i need to take into account the extra extension when attempting the solution or is it just f/k =l
or do i need to use f/k = l + x to calculate the amplitude
any help would be appriciated
Thanks