- #1
blackandyello
- 11
- 0
can somebody help me to know the proper way to solve this kind of problem.
correct answers are as follows, 6/10 or (36/60) , 4/10 , 3/5
the formula for probability is s/n ; where n is the total number of outcomes. I know how to get n by using 5P3 (5 ways taking 3 at a time). now, how do i get s (success outcome)? that confuses me. (I know that s(success outcome) is the number that will lock / target your condition) Thank you
Code:
Five employees of a firm are ranked from 1 to 5
based on their ability to program a computer.
Three of these employees are selected to fill
equivalent programming jobs. If all possible
choices of three (out of the five) are equally
likely, find the following probabilities
a The employee ranked number 1 is selected.
b The highest-ranked employee among those
selected has rank 2 or lower.
c The employees ranked 4 and 5 are selected.
correct answers are as follows, 6/10 or (36/60) , 4/10 , 3/5
the formula for probability is s/n ; where n is the total number of outcomes. I know how to get n by using 5P3 (5 ways taking 3 at a time). now, how do i get s (success outcome)? that confuses me. (I know that s(success outcome) is the number that will lock / target your condition) Thank you