- #1
RebWal
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I don't know how to solve for s. The question is How far up the incline will the block slide, and I was to solve it 2 ways.
I think I got the first way, and this is what I have so far for the 2nd way.
w=e2-e1
-Ff*s=e2-e1
-Moo g Cos pheta*s=1/2v^2-gh
-.21(9.8)Cos38*s=1/2(5.75)^2-9.8[s(Sin38)]
I'm not sure how to solve for s. If anyone could help me out I'd really appreciate it.
Oh by the way, this is grade 11 physics, and the first way I did it was using Fnet=ma and substituting a into v2^2=v1^2+2as and I got s=14m -- Not positive if that is right
I think I got the first way, and this is what I have so far for the 2nd way.
w=e2-e1
-Ff*s=e2-e1
-Moo g Cos pheta*s=1/2v^2-gh
-.21(9.8)Cos38*s=1/2(5.75)^2-9.8[s(Sin38)]
I'm not sure how to solve for s. If anyone could help me out I'd really appreciate it.
Oh by the way, this is grade 11 physics, and the first way I did it was using Fnet=ma and substituting a into v2^2=v1^2+2as and I got s=14m -- Not positive if that is right