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bacon
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The length of a rectangular swimming pool is twice its width. The pool is surrounded by a cement walk 4 ft wide. If the area of the walk is 748 square feet, determine the dimensions of the pool.
A= the total area bounded by the outer edge of the surrounding walk
W= the area of the walk
P= the area of the pool
x= the length of the short side of the pool
A=P+W
P=x2x=[tex]2x^{2}[/tex]
W=748
A=(x+8)(2x+8)=[tex]2x^{2}+24x+64[/tex]=[tex]2x^{2}+748
[/tex]
solving for x gives x=28.5 feet and 2x=57 feet
The answer sheet says the dimensions are 30 and 60 feet.
Where am I going wrong?
Thanks for any replies.
A= the total area bounded by the outer edge of the surrounding walk
W= the area of the walk
P= the area of the pool
x= the length of the short side of the pool
A=P+W
P=x2x=[tex]2x^{2}[/tex]
W=748
A=(x+8)(2x+8)=[tex]2x^{2}+24x+64[/tex]=[tex]2x^{2}+748
[/tex]
solving for x gives x=28.5 feet and 2x=57 feet
The answer sheet says the dimensions are 30 and 60 feet.
Where am I going wrong?
Thanks for any replies.