- #1
bethanyd
- 11
- 0
My friend came up with some solutions but I have doubts about them and was wondering if someone could help a bit.
A committee of 4 people is randomly selected from 5 married couples. What is the probability that a husband and wife do not belong to that committee?
I have All possible combinations = 4C10
then, divided into groups / sets:
P("all men"), P("3 men, 1 woman"), P("2 men, 2 women"), P("1 man, 3 women"), P("all women").
Then P(final answer) = [P("all men") + P("3 men, 1 woman") + P("2 men, 2 women") + P("1 man, 3 women") + P("all women")] / All possible combinations
My question, or more specifically, the part I am confused about is this: what stops a couple from being on the committee? Please explain this answer, I don't quite get it.
Thank you!
Homework Statement
A committee of 4 people is randomly selected from 5 married couples. What is the probability that a husband and wife do not belong to that committee?
The Attempt at a Solution
I have All possible combinations = 4C10
then, divided into groups / sets:
P("all men"), P("3 men, 1 woman"), P("2 men, 2 women"), P("1 man, 3 women"), P("all women").
Then P(final answer) = [P("all men") + P("3 men, 1 woman") + P("2 men, 2 women") + P("1 man, 3 women") + P("all women")] / All possible combinations
My question, or more specifically, the part I am confused about is this: what stops a couple from being on the committee? Please explain this answer, I don't quite get it.
Thank you!