- #1
shamieh
- 539
- 0
The miles per gallon of my car on a recent trip at time t was given by $mpg(t) = 30 + 10sin(t)$ where $0 <= t <= \pi$. Find the average value of $mpg(t)$ over this time interval.
So I'm kind of confused on how to do this. Here is what I have set up, let me know if I'm on the wrong track or not. Thanks in advance.
$\frac{1}{\pi} \int^\pi_0 (30 + 10sin(t)) \, dt$
$\frac{1}{\pi} [30x - 10cos(t)]$ $|^\pi_0$
$\frac{1}{\pi} ( [30\pi + 10] + [+10])$
$\frac{1}{\pi} [30\pi + 20]$
= $\frac{30\pi}{\pi} + \frac{20}{\pi} = \frac{30\pi + 20}{\pi}$
By the way I just completely guessed on how to do this, so this attempt may look idiotic lol. Thanks again.
So I'm kind of confused on how to do this. Here is what I have set up, let me know if I'm on the wrong track or not. Thanks in advance.
$\frac{1}{\pi} \int^\pi_0 (30 + 10sin(t)) \, dt$
$\frac{1}{\pi} [30x - 10cos(t)]$ $|^\pi_0$
$\frac{1}{\pi} ( [30\pi + 10] + [+10])$
$\frac{1}{\pi} [30\pi + 20]$
= $\frac{30\pi}{\pi} + \frac{20}{\pi} = \frac{30\pi + 20}{\pi}$
By the way I just completely guessed on how to do this, so this attempt may look idiotic lol. Thanks again.