Solving Satellite Orbits: Geostationary Radius & Speed

In summary, a geostationary orbit is a circular orbit around Earth at an altitude of approximately 35,786 km. It is important for satellite communication and weather forecasting as it allows for continuous coverage of a specific location on Earth. The geostationary radius is calculated using a formula that takes into account the gravitational constant, mass of Earth, and rotation period. Factors such as the mass of Earth and the radius of the orbit affect the geostationary speed, which is calculated using a different formula. However, a satellite cannot maintain a geostationary orbit indefinitely and may require occasional adjustments to counteract small changes in its orbit caused by atmospheric drag and gravitational perturbations.
  • #1
Jack16
13
0
Hi People I had problems solvin this question could you please help me,

The question:

On 19th June 1981,an experimental meteorological satellite of mass m=700 kg,was placed in a geostationary orbit usingthe launch vehicle Ariane.

Calculate:

a) the radius of geostationary orbit given that the period of revolution of the satellite is 23 h 56 m

b)the linear speed of such a satellite
 
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  • #2
Treat the orbit as an example of circular motion. What's the force pulling the satellite in a circle? Apply what you should know about centripetal acceleration.

Show your work if you need more help.
 
  • #3
in its orbit

Hi there,

I'd be happy to help you with this question. Let's break it down step by step.

a) To calculate the radius of a geostationary orbit, we can use Kepler's Third Law: T^2 = (4π^2/GM)*r^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the central body (Earth in this case), and r is the radius of the orbit. We can rearrange this equation to solve for r:

r = (GMT^2/4π^2)^(1/3)

Plugging in the values given in the question, we get:

r = [(6.67 x 10^-11 Nm^2/kg^2)(5.98 x 10^24 kg)(23 h 56 m)^2]/(4π^2)^(1/3)

= 4.22 x 10^7 meters

Therefore, the radius of the geostationary orbit is approximately 42,200 kilometers.

b) To calculate the linear speed of the satellite, we can use the formula v = 2πr/T, where v is the linear speed, r is the radius of the orbit, and T is the period of revolution. Plugging in the values from part a, we get:

v = (2π)(4.22 x 10^7 meters)/(23 h 56 m)

= 3.07 km/s

So the linear speed of the satellite in its geostationary orbit is approximately 3.07 kilometers per second.

I hope this helps! Let me know if you have any further questions or need clarification on any of the steps. Good luck!
 

FAQ: Solving Satellite Orbits: Geostationary Radius & Speed

What is a geostationary orbit and why is it important?

A geostationary orbit is a circular orbit around Earth at an altitude of approximately 35,786 km. Satellites in this orbit have an orbital period that matches the rotation of Earth, making them appear stationary from the ground. This is important for satellite communication and weather forecasting as it allows for continuous coverage of a specific location on Earth.

How is the geostationary radius calculated?

The geostationary radius is calculated using the formula r = (GMT^2)/(4π^2)^(1/3), where r is the radius, G is the gravitational constant, M is the mass of Earth, and T is the rotation period of Earth (86,164 seconds). This formula is derived from the relationship between orbital period and radius in circular orbits.

What factors affect the geostationary speed?

The geostationary speed is primarily affected by the mass of Earth and the radius of the orbit. As the mass of Earth increases, the speed decreases, and as the radius of the orbit increases, the speed also decreases. Other factors that can affect the geostationary speed include atmospheric drag and the presence of other objects in the orbit.

How is the geostationary speed calculated?

The geostationary speed is calculated using the formula v = √(GM/r), where v is the speed, G is the gravitational constant, M is the mass of Earth, and r is the radius of the orbit. This formula is derived from the relationship between orbital speed and radius in circular orbits.

Can a satellite maintain a geostationary orbit indefinitely?

No, a satellite cannot maintain a geostationary orbit indefinitely. Due to factors such as atmospheric drag and gravitational perturbations from other objects, satellites in geostationary orbit may experience small changes in their orbit over time. To counteract this, satellites may use small thrusters to make periodic adjustments to maintain their position in the orbit.

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