- #1
HALO3
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If
1) 1+2+3...+n =n(n+1)/2
Then what is
2) [tex]1^2+2^2+3^2+...+n^2= ?[/tex]
3) [tex]1^3+2^3+3^3+...+n^3= ?[/tex]
If someone can explain me how the first one came and how can i proceed to solve the second and third, it would be really grateful.
1) 1+2+3...+n =n(n+1)/2
Then what is
2) [tex]1^2+2^2+3^2+...+n^2= ?[/tex]
3) [tex]1^3+2^3+3^3+...+n^3= ?[/tex]
If someone can explain me how the first one came and how can i proceed to solve the second and third, it would be really grateful.