Solving Source Transforms: Finding v(out)

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In summary, the conversation discusses a problem with an op amp and a voltage source at the positive terminal. The question asks about incorporating this into the overall equation to find v(out) and how to consider the 370Ω resistor at the v(out) node. The suggested solution involves calculating v(out) as A(v(+) - v(-)) and using the equation -v1(Rf/Rin) = v(out).
  • #1
dwn
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Homework Statement



See Image

Homework Equations



Source Transforms

The Attempt at a Solution



After having simplified the positive terminal of the op amp, how is this calculated into the overall equation to find v(out)? Also, at the v(out) node, in what respect is the 370Ω resistor and voltage source considered? Would this be a subtraction from (Rf/R1)*v(out) equation?
 

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  • #2
dwn said:

Homework Statement



See Image

Homework Equations



Source Transforms

The Attempt at a Solution



After having simplified the positive terminal of the op amp, how is this calculated into the overall equation to find v(out)? Also, at the v(out) node, in what respect is the 370Ω resistor and voltage source considered? Would this be a subtraction from (Rf/R1)*v(out) equation?

Can you please post your work? This appears to be a pretty straightforward problem.
 
  • #3
Is there a specific equation we use, or do you know what it is called when the voltage source exists at the positive terminal of op amp?
 
  • #4
Can someone please provide a little bit of advice or direction on how to solve this. I have simplified the positive terminal of the op amp, and I know that v(out) = A(v(+) - v(-)) ... but I don't know what to calculate.
 
  • #5
berkeman said:
Can you please post your work? This appears to be a pretty straightforward problem.

One more chance before your thread gets deleted...
 
  • #6
-v1(Rf/Rin) = v(out)

23.9mV*(33k/1799.6) = v(out) = 0.4383 V
 

FAQ: Solving Source Transforms: Finding v(out)

How do I find the output voltage in a source transform circuit?

To find the output voltage (vout) in a source transform circuit, you can use the following steps:

  • Identify the source transform (voltage source or current source) and its value.
  • Replace the source transform with its equivalent impedance.
  • Solve the circuit using any applicable circuit analysis method (e.g. Ohm's law, Kirchhoff's laws).
  • Once you have calculated the current or voltage at the output node, use the relationship vout = Iout * Zout to find the output voltage.

Can I use source transforms in any circuit?

Yes, source transforms can be used in any circuit. However, they are most commonly used in circuits with multiple resistors, as they can simplify the circuit and make it easier to analyze.

What is the purpose of source transforms?

The purpose of source transforms is to simplify a circuit by replacing a voltage source with a series impedance or a current source with a parallel impedance. This can make the circuit easier to analyze and can also help in finding the equivalent impedance of the circuit.

How do I know which source transform to use?

The type of source transform to use (voltage or current) depends on the type of source in the circuit. If the source is a voltage source, it can be replaced with a series impedance, whereas a current source can be replaced with a parallel impedance.

Can I use multiple source transforms in a circuit?

Yes, you can use multiple source transforms in a circuit. However, it is important to note that only one source transform can be used at a time. This means that you must replace one source at a time and then analyze the circuit before moving on to the next source transform.

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