Solving Spring Homework: Angular Frequency & Amplitude

In summary, the block on a spring was pulled to the right and released at t=0s. It passes x=3.00cm at t=0.685s and x=-3.00cm at t=0.886s. To find the angular frequency, two equations can be set up using the given times and positions and solving for w by dividing the equations. The amplitude can then be found using the initial conditions and the solved value for w.
  • #1
XJellieBX
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0

Homework Statement


A block on a spring is pulled to the right and released at t=0s. It passes x=3.00cm at t=0.685s, and it passes x=-3.00cm at t=0.886s.
a) What is the angular frequency?
b) What is the amplitude?


Homework Equations


x(t)=Acos(wt+phi_0)


The Attempt at a Solution


Since the spring was initially pulled to the right, I assumed that the distance it was pulled would be the amplitude and with the initial conditions x0=Acos(phi_0)=A, I set phi_0=0. Plugging in the times and positions,
x(t=0.685s)=Acos(0.685w)
x(t=0.886s)=Acos(0.886w).
I tried solving for an equation for A and plugging it into the other equation, but it just ended up looking like a complicated mess. Any insight would be appreciated =)
 
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  • #2
There might be some insight to be gained by observing that the times given are for equal but opposite displacements about 0. Presumably the block and spring are at rest at x = 0.
 
  • #3
or you have

two equations
3.00=Acos(0.685w) and
-3.00=Acos(0.886w).

I would divide the equations, then A cancels, and you might have an easier time solving for w.
 

Related to Solving Spring Homework: Angular Frequency & Amplitude

1. What is angular frequency?

Angular frequency is a measure of how quickly an object is oscillating or rotating in a circular motion. It is represented by the symbol ω (omega) and is measured in radians per second.

2. How is angular frequency related to regular frequency?

Angular frequency and regular frequency are related by the equation ω = 2πf, where f is frequency in hertz. This means that angular frequency is equal to 2π times the regular frequency.

3. How do you calculate the amplitude of a spring oscillation?

The amplitude of a spring oscillation is the maximum displacement of the object from its equilibrium position. It can be calculated using the equation A = x_max - x_min, where x_max is the maximum displacement and x_min is the minimum displacement.

4. What factors affect the angular frequency of a spring oscillation?

The angular frequency of a spring oscillation is affected by the mass of the object, the spring constant, and the length of the spring. These factors can be manipulated to change the angular frequency of the oscillation.

5. How can we use angular frequency to determine the period of a spring oscillation?

The period of a spring oscillation can be calculated using the equation T = 2π/ω, where T is the period in seconds and ω is the angular frequency. This means that the period is inversely proportional to the angular frequency.

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