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maxkor
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Solve in R $\tan^2x + \tan^2{2x} + \cot^2{3x} = 1$.
No solution.maxkor said:Solve in R $\tan^2x + \tan^2{2x} + \cot^2{3x} = 1$.
Wouldst thou still attempt to solve it given that you've already had a glimpse that it doesn't have a solution or do you just want to show that it doesn't have a solution?maxkor said:But without desmos etc.
The first step in solving this equation is to rewrite it in terms of sine and cosine using the identity $\tan^2x = \frac{\sin^2x}{\cos^2x}$ and $\cot^2x = \frac{\cos^2x}{\sin^2x}$.
Yes, this equation can be solved algebraically by using trigonometric identities and solving for the unknown variable.
Yes, there are restrictions on the values of x since the tangent and cotangent functions are undefined at certain values. In this equation, x cannot equal any odd multiple of $\frac{\pi}{2}$ or any multiple of $\pi$.
Yes, you can check your solution by plugging it back into the original equation and verifying that it satisfies the equation.
Yes, this equation can be solved using a graphing calculator by graphing the left side of the equation and finding the x-intercepts, which represent the solutions.