Solving the Geodesic Equation: Raising Contravariant Indices

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The discussion focuses on manipulating the geodesic equation while maintaining its non-affine form. The participants explore how to raise contravariant indices in the derivative on the left-hand side of the equation. It is confirmed that the expression k^{a ;b} k_{b} = \kappa k^{a} is valid, with the transformation of the covariant derivative being a key point. The conversation emphasizes the importance of understanding how the covariant derivative behaves as a tensor compared to partial derivatives. Overall, the exchange clarifies the manipulation of indices in the context of the geodesic equation.
Pacopag
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Homework Statement


I would like to manipulate the geodesic equation.


Homework Equations


The geodesic equation is usually written as
k^{a}{}_{;b} k^{b}=\kappa k^{a} (it is important for my purpose to keep it in non-affine form).
It is clear that by contracting with the metric we may write alternatively
k_{a ;b} k^{b} = \kappa k_{a}.
What I would like to know is how to raise to a contravariant indices in the derivative on the left-hand side.

The Attempt at a Solution


If I had to guess, I would like to be able to write something like.
k^{a ;b} k_{b}=\kappa k^{a}.
Is this a valid form of the geodesic equation?
 
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Sure. g^{a b} k_{;b}=k^{;a}.
 
Thank you for your reply Dick.
But how do you explain the lowering of the b index in the second factor on the left-hand side?
 
On the LHS you've got {k^a}_{;b}k^b=k^{a;c}g_{cb}k^b=k^{a;c}k_c=k^{a;b}k_b
 
Excellent! Thank you both very much.
 
Pacopag said:
Excellent! Thank you both very much.

The crucial point is that the covariant derivative transforms as a tensor, unlike say, the partial derivative.
 

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