- #1
boxelderbug
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I'm not really good at physics so relevant any feedback would be helpful. Here's the question;
At the instant a traffic light turns green, a car starts with a constant velocity of 6.0 ft/s. At the same instant a truck, traveling with a constant speed of 34 ft/s, overtakes and passes the car. How far beyond the traffic light will the car overtake the truck?
This is what I got so far;
The acceleration of both the truck and the car is zero.
truck: x=34(ft/s)t
Car: x=(1/2)(6.0ft/s+34ft/s)t=20t
This is where I get stuck. Can you tell me what I'm doing wrong or what I'm not doing?
I know that I will have to use two equations with two unknowns. By doing this I should get me the time it takes for the car to catch up to truck. Then I can plug the time back into get the distance.
At the instant a traffic light turns green, a car starts with a constant velocity of 6.0 ft/s. At the same instant a truck, traveling with a constant speed of 34 ft/s, overtakes and passes the car. How far beyond the traffic light will the car overtake the truck?
This is what I got so far;
The acceleration of both the truck and the car is zero.
truck: x=34(ft/s)t
Car: x=(1/2)(6.0ft/s+34ft/s)t=20t
This is where I get stuck. Can you tell me what I'm doing wrong or what I'm not doing?
I know that I will have to use two equations with two unknowns. By doing this I should get me the time it takes for the car to catch up to truck. Then I can plug the time back into get the distance.