Solving the Problem: Deriving ∂2φ/∂x2

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In summary, the student attempted to find the derivative of φ with respect to x, but was unable to do so because they were missing a term in the equation. Once they corrected the equation, they were able to find the derivative of φ with respect to x.
  • #1
whatisreality
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Homework Statement


Let φ=φ(r) and r=√x2+y2+z2. Find ∂2φ/∂x2.
Show that it can be written as (1/r + x2/r3)∂φ/∂r + x2/r22φ/∂r2.

Homework Equations


Use the identity ∂r/∂x = x/r.

The Attempt at a Solution


I think I know ∂φ/∂x. Using the chain rule, it's ∂r/∂x ∂φ/∂r. That gives x/r ∂φ/∂r. If that's wrong it might be because I know you have to take account of all dependences, but I don't actually know how to.
So assuming that's ok, I then need to use the product rule, and that gave me
1/r ∂φ/∂r + ∂φ/∂x ∂φ/∂r ∂r/∂x.
Which I know is wrong, because it's a show that question!
 
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  • #2
whatisreality said:

Homework Statement


Let φ=φ(r) and r=√x2+y2+z2. Find ∂2φ/∂x2.
Show that it can be written as (1/r + x2/r3)∂φ/∂r + x2/r22φ/∂r2.

Homework Equations


Use the identity ∂r/∂x = x/r.

The Attempt at a Solution


I think I know ∂φ/∂x. Using the chain rule, it's ∂r/∂x ∂φ/∂r. That gives x/r ∂φ/∂r.
I would write this as dφ/dr ∂r/∂x or φ'(r)∂r/∂x = dφ/dr (x/r). φ is a function of r alone, so the derivative for this function is the regular derivative instead of the partial derivative. Now use the product rule to get ∂2φ/∂x2.
whatisreality said:
If that's wrong it might be because I know you have to take account of all dependences, but I don't actually know how to.
So assuming that's ok, I then need to use the product rule, and that gave me
1/r ∂φ/∂r + ∂φ/∂x ∂φ/∂r ∂r/∂x.
Which I know is wrong, because it's a show that question!
 
  • #3
Mark44 said:
I would write this as dφ/dr ∂r/∂x or φ'(r)∂r/∂x = dφ/dr (x/r). φ is a function of r alone, so the derivative for this function is the regular derivative instead of the partial derivative. Now use the product rule to get ∂2φ/∂x2.
I'm doing something wrong. So I got ∂2φ/∂x2 = 1/r ∂φ/∂r + ∂/dr (dφ/dr) ∂r/∂x x/r. This doesn't give me the answer, it gives
2φ/∂x2 = 1/r dφ/dr + x2/r22φ/∂r2, but I really can't see what's wrong!
 
  • #4
I'm missing a whole term: x2/r3 dφ/dr.
 
  • #5
whatisreality said:
I'm doing something wrong. So I got ∂2φ/∂x2 = 1/r ∂φ/∂r + ∂/dr (dφ/dr) ∂r/∂x x/r. This doesn't give me the answer, it gives
2φ/∂x2 = 1/r dφ/dr + x2/r22φ/∂r2, but I really can't see what's wrong!
You don't show the work leading up to this, but I'm guessing that you did this: ##\frac{\partial}{\partial x} \frac{x}{r} = \frac{1}{r}##. If so, that's wrong, since you would be treating r as a constant. In fact, r is a function of x (and y and z).
 
  • #6
Ohhh... That's exactly what I did. I always forget that!
 
  • #7
Should be y2+z2/r3 then.
Yep, that gives the right answer! Thank you, I was getting really confused.
 

FAQ: Solving the Problem: Deriving ∂2φ/∂x2

1. What is the purpose of solving the problem of deriving ∂2φ/∂x2?

The purpose of solving this problem is to understand the rate of change of a function φ with respect to the variable x. This can be useful in various fields such as physics, engineering, and mathematics.

2. What are the steps involved in solving this problem?

The first step is to identify the function φ and the variable x. Then, we use the chain rule to find the first derivative of φ with respect to x. Next, we apply the chain rule again to find the second derivative, which is ∂2φ/∂x2.

3. What is the significance of the second derivative in this problem?

The second derivative ∂2φ/∂x2 is significant because it represents the rate of change of the rate of change of φ with respect to x. This can provide information about the concavity and inflection points of the function φ.

4. Can this problem be solved for any type of function?

Yes, this problem can be solved for any differentiable function φ with respect to the variable x. However, the complexity of the solution may vary depending on the type of function.

5. How is this problem relevant in real-world applications?

Solving this problem is relevant in real-world applications as it can help us understand the behavior and relationships between different variables in various fields such as physics, engineering, and economics. It is also essential in optimization and curve fitting techniques.

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