- #1
yankee
- 8
- 0
A train is moving parallel and adjaceent to a highway with a constant speed of 33 m/s, initially a car is 37 m behind the train, traveling in the same direction as the train at 47 m/s and accelerating at 5 m/s^2.
What is the speed of the car just as it passes the train? Answer in units of m/s
----
Basically I found that:
Vo= 47 m/s
a= 5 m/s^2
x= 37 m
----
Somehow i found out that
t= .869919 s
Vf= 50.7838
---
However my answer is incorrect. I know the train is still moving but I can't seem to figure out how to connect the train factor and the car factor. How would I go about to solving this question?
thanks
What is the speed of the car just as it passes the train? Answer in units of m/s
----
Basically I found that:
Vo= 47 m/s
a= 5 m/s^2
x= 37 m
----
Somehow i found out that
t= .869919 s
Vf= 50.7838
---
However my answer is incorrect. I know the train is still moving but I can't seem to figure out how to connect the train factor and the car factor. How would I go about to solving this question?
thanks