Solving the Speed of a Projectile Passes an Observation Satellite

  • Thread starter talaroue
  • Start date
In summary, a huge cannon on an airless planet with a radius of 6.00×10^6 m and a mass of 3.06×10^24 kg fires a projectile at 5270 m/s. An observation satellite orbits at a height of 4103.30 km. The projectile's speed as it passes the satellite can be calculated by equating the kinetic energy at firing plus potential energy at the surface to the potential energy at the satellite plus the kinetic energy of the projectile. The equation should be set up as -0.5Vi^2 - GMm/R = -GMm/(R+h) + 0.5Vf^2, and after solving for Vf, the mass of
  • #1
talaroue
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Homework Statement


A huge cannon is assembled on an airless planet. The planet has a radius of 6.00×106 m and a mass of 3.06×1024 kg. The cannon fires a projectile straight up at 5270 m/s.
An observation satellite orbits the planet at a height of 4103.30 km. What is the projectile�s speed as it passes the satellite?


Homework Equations


K=mv^2/2
U=-GMm/r



The Attempt at a Solution


Initially: Ki and Ui are both present
Finally: Ki and Uf are both present again
CORRECT?
so i have the equation
Ki-Ui=Kf-Uf
wanting to solve for velocity at a certain point Uf actually is GMm/(R+H)
CORRECT?
So then I solved for Vf and get ...
squareroot (2(Ki-Ui+Uf)/m)

Then i plug and go...WHY ISN'T WORKING
 
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  • #2
You seem to have the basic idea.

Kinetic energy at firing + potential energy gravity at surface = potential energy at satellite + kinetic energy of projectile.
 
  • #3
after plugging in the KE and PE equations i came up with...-2(-.5Vi^2+GM/R-GM/(R+h))
square root of the whole thing.
 
  • #4
so instead of using the mass of the planet i should use mass of the sataellite?

EDIT: I don't have the mass of the satellite so I believe I have it set up right.
 
  • #5
talaroue said:
so instead of using the mass of the planet i should use mass of the sataellite?

No. Of course not.

The Mass of the Planet and G give you a way to figure your potential energy ...

U = -GM/r

So ...

at surface U = the above.
at the satellite U = -GM/(r+h)

(Don't forget the sign.)
 
  • #6
wanting to solve for velocity at a certain point Uf actually is GMm/(R+H)

So then the way I set it up is right?
 
  • #7
talaroue said:
So then the way I set it up is right?

So long as you have also accounted for the potential energy at the surface as well.
 
  • #8
You forgot that the satellite is in orbit. It's moving, too.
 
  • #9
I attached my equation.
 

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  • #10
D H said:
You forgot that the satellite is in orbit. It's moving, too.

you can't just assume it isn't moving?
 
  • #11
I don't think they are asking for the speed relative to the satellite.

Merely the speed at the height (radius) of the satellite's orbit.
 
  • #12
thats what I figured. I figured that they just wanted the distance. Is my equation correct that i attached a few posts back?
 
  • #13
talaroue said:
thats what I figured. I figured that they just wanted the distance. Is my equation correct that i attached a few posts back?

Looks like the - in front of the 2 is not useful.

I would examine they way you treated the mass of the projectile ... as a suggestion.
 
  • #14
The mass should cancel. i meant to erase it, and the 2 shouldn't be negative. I just worked through that equation and it said the answer is wrong.
 
Last edited:
  • #15
talaroue said:
It cancels.

Not in the equation you supplied.
 
  • #16
Opps that is my bad, I knew it canceled in my mind but when I re wrote it i forgot to cancel it even though I canceled the others.

EDIT: WHen i worked through it, i didn't use the negative or the mass and it was wrong
 
  • #17
Has this question been resolved?
 
  • #18
talaroue said:
Opps that is my bad, I knew it canceled in my mind but when I re wrote it i forgot to cancel it even though I canceled the others.

EDIT: WHen i worked through it, i didn't use the negative or the mass and it was wrong

Maybe show your work? Perhaps you have a simple error?
 
  • #19
Wouldn't it just be easier to use [tex]S(t)=-gt^{2}+V_{o}t+h_{o}[/tex]?
 
  • #20
No. That equation assumes a uniform gravity field.
 
  • #21
hmmmm i was never able to get it.
 
  • #22
talaroue said:
hmmmm i was never able to get it.

Maybe show your actual calculation?
 
  • #23
ok ill try to get that on here hold on.
 

FAQ: Solving the Speed of a Projectile Passes an Observation Satellite

What is the speed of a projectile passing an observation satellite?

The speed of a projectile passing an observation satellite can vary greatly depending on factors such as the type of projectile, its initial velocity, the distance from the satellite, and the gravitational pull of the satellite.

How is the speed of a projectile passing an observation satellite calculated?

The speed of a projectile passing an observation satellite is calculated using the formula: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken for the projectile to pass the satellite.

What is the role of gravitational pull in determining the speed of a projectile passing an observation satellite?

The gravitational pull of the satellite affects the acceleration of the projectile, which in turn affects its speed. The greater the gravitational pull, the higher the acceleration and the faster the projectile will pass the satellite.

How does the distance from the satellite impact the speed of a projectile passing it?

The distance from the satellite also plays a role in determining the speed of a projectile passing it. The closer the projectile is to the satellite, the stronger the gravitational pull and the faster the projectile will pass. However, if the distance is too close, the projectile may collide with the satellite.

Are there any other factors that can affect the speed of a projectile passing an observation satellite?

Yes, there are other factors that can affect the speed of a projectile passing an observation satellite. These include air resistance, the shape and size of the projectile, and any external forces acting on the projectile such as wind or other celestial bodies.

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