- #1
BriannaUND
- 12
- 0
I'm having problems with the following two problems. Thank you for any help!
72) A skiier coasts down a very smooth 10-meter high slope. If the speed of the skiier on the top of the slope is 5.0m/s, what is his speed at the bottom of the slope?
I calculated 2gy= v2 and plugged in v= sq root (2x 9.8m/s2 x10m)= 14m/s Does this look correct? We did an example like this in class but we used vinitial = 0 m/s where its 5.0m/s in this problem so I don't know how to go on from there!
79) In #72, if the skiier has a mass of 60kg and the force of friction retards his motion by doing 2500 J of work, what is his speed at the bottom of the slope?
I know that there is an equation v= sq root (vo2 - 2ukmgd) but I don't know where to plug #s in or if this is even the right equation?!
Thanks again!
72) A skiier coasts down a very smooth 10-meter high slope. If the speed of the skiier on the top of the slope is 5.0m/s, what is his speed at the bottom of the slope?
I calculated 2gy= v2 and plugged in v= sq root (2x 9.8m/s2 x10m)= 14m/s Does this look correct? We did an example like this in class but we used vinitial = 0 m/s where its 5.0m/s in this problem so I don't know how to go on from there!
79) In #72, if the skiier has a mass of 60kg and the force of friction retards his motion by doing 2500 J of work, what is his speed at the bottom of the slope?
I know that there is an equation v= sq root (vo2 - 2ukmgd) but I don't know where to plug #s in or if this is even the right equation?!
Thanks again!