- #1
Sylis
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A 1.0 kg wood block is pressed against a vertical wood wall by a 12 N force (into the wall, at a 30 degrees angle up from the horizontal). if the block is initially at rest, will it move upward, move downward, or stay at rest?
I'm working on the problem above, and through Google found this link. I understand how to accomplish the problem. However, I'm having trouble identifying the forces in play. My teacher wants us to accomplish these sort of problems a very specific sort of way.
1) Identify forces (In this case I'd have horizontal forces and vertical forces)
2)Draw a free-body diagram
3) Apply Newton's second law in Component form. (ƩFx=max/ƩFy=may)
And solve.
So far my horizontal force is the Push force (30cos12) and my vertical forces are Static Friction, weight and also Push force (30sin12).
"Fnet(x) = Fn - Fpush(x) , and since Fnet(x) is 0, then Fn = Fpush (x)" (from link)
I'm not understanding where he is getting Fn from or what Fn even stands for, I thought perhaps it was normal force, but there is no horizontal surface the block of wood is on, so there should be no normal force.
I'm working on the problem above, and through Google found this link. I understand how to accomplish the problem. However, I'm having trouble identifying the forces in play. My teacher wants us to accomplish these sort of problems a very specific sort of way.
1) Identify forces (In this case I'd have horizontal forces and vertical forces)
2)Draw a free-body diagram
3) Apply Newton's second law in Component form. (ƩFx=max/ƩFy=may)
And solve.
So far my horizontal force is the Push force (30cos12) and my vertical forces are Static Friction, weight and also Push force (30sin12).
"Fnet(x) = Fn - Fpush(x) , and since Fnet(x) is 0, then Fn = Fpush (x)" (from link)
I'm not understanding where he is getting Fn from or what Fn even stands for, I thought perhaps it was normal force, but there is no horizontal surface the block of wood is on, so there should be no normal force.