Solving Work Done Problem: Minimize Work, Angle & Magnitude of Force

In summary, the problem involves finding the angle at which a driving force should be directed to minimize the work done in moving a block a horizontal distance of 10m with nonzero velocity. The direction of motion should be perpendicular to the force, but this would result in zero work being done. A slight horizontal component would be needed in order to move the block as required. This is a college assessed problem and it appears that the person creating it may not have realized this.
  • #1
sorax123
34
0

Homework Statement


There is a block of weight mg sitting on a horizontal table with a coefficient of kinetic friction u, at what angle to the horizontal should one direct a driving force to minimise work done in moving the block a horizontal distance of 10m with nonzero velocity and what is the magnitude of that work?

Homework Equations


W=integral(F.ds)
F=uR

The Attempt at a Solution


Looking at this problem I cannot see why it would not be 90degrees and zero work being done because the direction of motion would be perpendicular to the force so F.ds is 0. But this is a 7 mark question surely that explanation isn't worth 7 marks have I missed something?
Thank you
 
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  • #2
sorax123 said:
Looking at this problem I cannot see why it would not be 90degrees and zero work being done because the direction of motion would be perpendicular to the force so F.ds is 0.
That would certainly minimize the work! But would that allow you to move the block as required?
 
  • #3
Doc Al said:
That would certainly minimize the work! But would that allow you to move the block as required?
So would you say 89.999999999...?
 
  • #4
On second thought, I think you are right. (For all practical purposes: yes, you'd need some slight horizontal component.) I suspect the person creating the problem didn't realize this. (I suspect this is not a textbook problem.)
 
  • #5
Doc Al said:
On second thought, I think you are right. (For all practical purposes: yes, you'd need some slight horizontal component.) I suspect the person creating the problem didn't realize this. (I suspect this is not a textbook problem.)
It is a college assessed problem bit annoying really
 

FAQ: Solving Work Done Problem: Minimize Work, Angle & Magnitude of Force

How do I minimize work in a work done problem?

In order to minimize work in a work done problem, you need to minimize the magnitude of force and the angle of force. This can be achieved by finding the optimal angle and force that will result in the least amount of work.

Why is it important to minimize the work in a work done problem?

Minimizing work in a work done problem is important because it allows for the most efficient use of energy. This can result in cost savings and increased productivity.

What is the relationship between work, force, and angle in a work done problem?

In a work done problem, the amount of work done is directly proportional to the force applied and the displacement of the object. The angle of force also plays a role in determining the amount of work done, as it affects the direction of the force and the resulting displacement.

How do I calculate the work done in a work done problem?

The work done in a work done problem can be calculated using the equation W = F * d * cosθ, where W is work, F is force, d is displacement, and θ is the angle between the force and the displacement.

Can work be negative in a work done problem?

Yes, work can be negative in a work done problem. This occurs when the angle between the force and the displacement is greater than 90 degrees, resulting in a negative value for work. This can happen when the force is acting against the direction of displacement, or when the angle is obtuse.

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