Solving (x^2)y`` -xy`+y=0: Tips for Beginners

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In summary, the conversation suggests using the power series method (Frobenius) to solve a linear ODE with an "Euler-type" or "equipotential" equation. It is recommended to let y= xr and find r to satisfy the equation. This method may not be necessary, but it is a good starting point.
  • #1
asdf1
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for the following question:
find a basis of solutions for
(x^2)y`` -xy`+y=0


my problem:
i haven't a clue on where to start~
can someone give some tips for starters?
 
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  • #2
Have you learned power series methods (Frobenius) for solving linear ODEs?
 
  • #3
no, not yet
 
  • #4
It's not necessary to use power expansions here. This is an "Euler-type" or "equipotential" equation- the degree of x in each term is equal to the order of the derivative.

Hint- let y= xr for unknown r, then find r so that the equation is satisfied.

(That will get you started, but that's actually the easy part!)
 
  • #5
ok, i'll try that!
 

FAQ: Solving (x^2)y`` -xy`+y=0: Tips for Beginners

1. What is the formula for solving (x^2)y`` -xy`+y=0?

The formula for solving this type of equation is called the quadratic formula and is expressed as:
x = (-b ± √(b^2 - 4ac)) / 2a
where a, b, and c are coefficients of the equation (x^2)y`` -xy`+y=0.

2. Can this equation be solved using algebra or do I need to use a calculator?

This equation can be solved using algebra, specifically the quadratic formula. However, if the coefficients are large or involve decimals, using a calculator may be more efficient.

3. What does the solution to this equation represent?

The solution to this equation represents the values of x that make the equation true. In other words, it is the x-intercepts or roots of the equation.

4. Are there any special cases or exceptions to solving this type of equation?

Yes, there are a few special cases to consider when solving this type of equation. If the coefficient of x^2 is 0, the equation becomes linear and can be solved using basic algebra. If the discriminant (b^2 - 4ac) is negative, the equation has no real solutions and the graph will not intersect the x-axis. Lastly, if the discriminant is 0, the equation has one repeated solution.

5. Are there any other methods or tips for beginners when solving this type of equation?

One helpful tip is to always check your solutions by plugging them back into the original equation. Also, make sure to simplify as much as possible before using the quadratic formula. It may also be helpful to practice factoring and simplifying expressions before attempting to solve this type of equation.

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