Solving Zn(NO3)2 and Al(NO3)3 Problems with NaOH

  • Thread starter dagg3r
  • Start date
In summary, to determine the number of moles of Zn(NO3)2 and Al(NO3)3 in a solution, you can use the given concentrations and volumes and the formula moles = concentration (mol/L) x volume (L). The balanced chemical equation for the reaction between Zn(NO3)2, Al(NO3)3, and NaOH is 2Zn(NO3)2 + 6NaOH + 2Al(NO3)3 → 2Zn(OH)2 + 2NaNO3 + 2Al(OH)3. To calculate the limiting reagent, compare the moles of each reactant to the stoichiometric ratio, and to determine the excess react
  • #1
dagg3r
67
0
Zn(NO3)2 problem!

Zn(NO3)2 will react with NaOH, precipitate will form, but continueing adding sodium hydroxide will dissolve Zn(OH)2.

2NaOH + Zn(NO3)2 -> Zn(OH)2 + 2NaNO3

Zn(OH)2 + 2NaOH -> Na2ZnO2 + 2H2O

It happens similarly with Al(NO3)3 reacting with NaOH.

3NaOH + Al(NO3)3 -> Al(OH)3 + 3NaNO3

Al(OH)3 + NaOH -> NaAlO2 + 2H2O
 
Chemistry news on Phys.org
  • #2
So what is the problem?

The Bob (2004 ©)
 
  • #3
Post Trans. cations react extensively with OH- and ppts tend to dissolve as metal ions converts to a soluable hydroxo complex ion.
 

FAQ: Solving Zn(NO3)2 and Al(NO3)3 Problems with NaOH

How do I determine the number of moles of Zn(NO3)2 and Al(NO3)3 in a solution?

To determine the number of moles of Zn(NO3)2 and Al(NO3)3, you will need to use the given concentrations and volumes of the solutions. The formula for calculating moles is moles = concentration (mol/L) x volume (L). Make sure to convert the volume to liters if it is given in milliliters.

What is the balanced chemical equation for the reaction between Zn(NO3)2, Al(NO3)3, and NaOH?

The balanced chemical equation for this reaction is 2Zn(NO3)2 + 6NaOH + 2Al(NO3)3 → 2Zn(OH)2 + 2NaNO3 + 2Al(OH)3. This equation shows the reactants on the left side and the products on the right side, with the same number of atoms for each element on both sides.

How do I calculate the limiting reagent in this reaction?

To calculate the limiting reagent, you will need to compare the number of moles of each reactant to the stoichiometric ratio in the balanced chemical equation. The reactant with the lower number of moles compared to the ratio is the limiting reagent, as it will be completely consumed in the reaction.

How do I determine the amount of excess reactant in this reaction?

To determine the amount of excess reactant, you will need to first calculate the number of moles of the limiting reagent that is consumed in the reaction. Then, using the stoichiometric ratio in the balanced equation, calculate the number of moles of the other reactant that would be needed for complete reaction. The difference between the initial amount and the required amount is the excess reactant.

What is the purpose of adding NaOH to a solution of Zn(NO3)2 and Al(NO3)3?

The purpose of adding NaOH is to neutralize the acidic solutions of Zn(NO3)2 and Al(NO3)3. This reaction also forms precipitates of Zn(OH)2 and Al(OH)3, which can be separated and used for further experiments or analysis.

Similar threads

TiO2 Photocatalyst to replicate making a photocatalytic PVA film
Replies
1
Views
1K
On operation principles of zinc-manganese alkaline batteries
Replies
1
Views
2K
What Is the White Powder from Ultrasonic Humidifiers and Is It Harmful?
2
Replies
42
Views
6K
Calculating Theoretical Yield for Copper Reactions: Help with Homework
Replies
16
Views
22K
Solving Volumetric Analysis Questions with NaOH & H3PO4
Replies
1
Views
2K
Net Ionic Equations: Answers to Questions
Replies
2
Views
8K
Understanding Zn(OH)2 & Al(OH)3: Ampiprotic Properties
Replies
2
Views
9K
How to Solve Simple Stoichiometry Problems Involving Solvents?
Replies
7
Views
3K
AP Chemistry exam question (multi-choice): What should I know?
Replies
1
Views
5K
Solving Electrochemistry Lab with Al+3, Cu+2, Fe+3, Zn+2, KNO3
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top