- #1
jehan4141
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A student typing in a computer cluster generates a sound level of 55 dB. What will the dB level the night before essays are due when there are 30 equally noisy students working in the cluster?
dBo = 55
Ihearing = 1E-12 W/m2
Bo = 10log(I/Ihearing)
55 = 10log(I/Ihearing)
55 = 10log(I/1.0E-12)
I = 3.16227766E-7 W/m2
If there are 30 other individuals, this makes a total of 31 individuals.
Itotal = 31 x I = 31 x 3.16227766E-7
Itotal = 9.80E-6 W/m2
Btotal = 10log(Itotal/Ihearing) = 10log(9.80E-6/1E-12)
Btotal = 69.91 dB ?
The answer says that it is 63.8 dB. Please can somebody help me find where in my logic I have failed? Thank you so very much everyone!
dBo = 55
Ihearing = 1E-12 W/m2
Bo = 10log(I/Ihearing)
55 = 10log(I/Ihearing)
55 = 10log(I/1.0E-12)
I = 3.16227766E-7 W/m2
If there are 30 other individuals, this makes a total of 31 individuals.
Itotal = 31 x I = 31 x 3.16227766E-7
Itotal = 9.80E-6 W/m2
Btotal = 10log(Itotal/Ihearing) = 10log(9.80E-6/1E-12)
Btotal = 69.91 dB ?
The answer says that it is 63.8 dB. Please can somebody help me find where in my logic I have failed? Thank you so very much everyone!