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Malavin
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Okay, I have this problem worked out, but I have no clue if my answers are right. Could someone please check my work and give me some confidence or show me where I may have messed up.
Two loudspeakers, one of them generates sound with 400 W power the other with 100 W. The sound is generated isotropically (the same in all directions) from each loudspeaker. A listener is seated 20m from the 100 W loudspeaker and 40 m from the other loudspeaker. A signal generator drives the two speakers in phase with the same frequency. The frequency is swept through the audible range from 20-20,000 Hz.
a) What is the ratio of the intensities of the two sounds (I(for 400W)/I(for 100W)) at the listener's position?
b) What are the two highest frequencies at which the listener will hear a maximum signal because of constructive interference?
c) What are the two highest frequencies at which the listener will hear a minimum signal because of destructive interference?
d) Assuming a single frequency of sound (f= 5000Hz) from the 400 W loudspeaker. What is the displacement amplitude of the sound waves that arrives at the listener's position from the 400 W loudspeaker only?
I = Ps/(4πr2)
I = 0.5ρvω2sm2
ΔL/λ = 0, 1, 2... (fully constructive interference)
ΔL/λ = 0.5, 1.5, 2.5... (fully destructive interference)
v = λf
vair = 343 m/s
ρair = 1.21 kg/m3
a) I1 = Ps/(4πr2) = 400/(4π402) = 1.99*10-2 W/m2
I2 = 100/(4π202) = 1.99*10-3 W/m2
I1/I2 = 10
b) ΔL/λ = ΔL/(v/f) = fΔL/v = f(40-20)/343 = 0, 1, 2...
f = (0, 1, 2...)*17.15 Hz
fmaxf = 20,000 Hz
Looking for two highest frequencies: (n)17.15 Hz ≤ 20,000 Hz
n ≤ 1166.18
nmax = 1165, 1166
fmax = 19,979.75 Hz, 19,996.9 Hz
c)f = (0.5, 1.5, 2.5...)*17.15 Hz
(n)17.15 Hz ≤ 20,000 Hz
n ≤ 1166.18
nmax = 1164.5, 1165.5
fmax = 19,971.18 Hz, 19,988.33 Hz
d)ω = 2πf = 2π(5000) = 10000π
I = 0.5ρvω2sm2
sm = √(2I/(ρvω2))
sm = 3.18*10-7 m
Homework Statement
Two loudspeakers, one of them generates sound with 400 W power the other with 100 W. The sound is generated isotropically (the same in all directions) from each loudspeaker. A listener is seated 20m from the 100 W loudspeaker and 40 m from the other loudspeaker. A signal generator drives the two speakers in phase with the same frequency. The frequency is swept through the audible range from 20-20,000 Hz.
a) What is the ratio of the intensities of the two sounds (I(for 400W)/I(for 100W)) at the listener's position?
b) What are the two highest frequencies at which the listener will hear a maximum signal because of constructive interference?
c) What are the two highest frequencies at which the listener will hear a minimum signal because of destructive interference?
d) Assuming a single frequency of sound (f= 5000Hz) from the 400 W loudspeaker. What is the displacement amplitude of the sound waves that arrives at the listener's position from the 400 W loudspeaker only?
Homework Equations
I = Ps/(4πr2)
I = 0.5ρvω2sm2
ΔL/λ = 0, 1, 2... (fully constructive interference)
ΔL/λ = 0.5, 1.5, 2.5... (fully destructive interference)
v = λf
vair = 343 m/s
ρair = 1.21 kg/m3
The Attempt at a Solution
a) I1 = Ps/(4πr2) = 400/(4π402) = 1.99*10-2 W/m2
I2 = 100/(4π202) = 1.99*10-3 W/m2
I1/I2 = 10
b) ΔL/λ = ΔL/(v/f) = fΔL/v = f(40-20)/343 = 0, 1, 2...
f = (0, 1, 2...)*17.15 Hz
fmaxf = 20,000 Hz
Looking for two highest frequencies: (n)17.15 Hz ≤ 20,000 Hz
n ≤ 1166.18
nmax = 1165, 1166
fmax = 19,979.75 Hz, 19,996.9 Hz
c)f = (0.5, 1.5, 2.5...)*17.15 Hz
(n)17.15 Hz ≤ 20,000 Hz
n ≤ 1166.18
nmax = 1164.5, 1165.5
fmax = 19,971.18 Hz, 19,988.33 Hz
d)ω = 2πf = 2π(5000) = 10000π
I = 0.5ρvω2sm2
sm = √(2I/(ρvω2))
sm = 3.18*10-7 m